We want to conduct a hypothesis test of the claim that the population mean reading speed of second graders is different from 30.1 words per minute. So, we choose a random sample of students' reading speeds. The sample has a mean of 30.8 words per minute and a standard deviation of 2.9 words per minute. For each of the following sampling scenarios, choose an appropriate test statistic for our hypothesis test on the population mean. Then calculate that statistic. Round your answers to two decimal places. (a) The sample has size 10, and it is from a normally distributed population with an unknown standard deviation. O z = Ot = ] O It is unclear which test statistic to use. (b) The sample has size 14, and it is from a population with a distribution about which we know very little. O z = O t O It is unclear which test statistic to use.

We want to conduct a hypothesis test of the claim that the population mean reading speed of second graders is different from 30.1 words per minute. So, we choose a random sample of students' reading speeds. The sample has a mean of 30.8 words per minute and a standard deviation of 2.9 words per minute. For each of the following sampling scenarios, choose an appropriate test statistic for our hypothesis test on the population mean. Then calculate that statistic. Round your answers to two decimal places. (a) The sample has size 10, and it is from a normally distributed population with an unknown standard deviation. O z = Ot = ] O It is unclear which test statistic to use. (b) The sample has size 14, and it is from a population with a distribution about which we know very little. O z = O t O It is unclear which test statistic to use.

Name: We want to conduct a hypothesis test of the claim that the population
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: We want to conduct a hypothesis test of the claim that the population mean reading speed of second graders is different from 30.1 words perminute. So, we choose a random sample of students' reading speeds. The sample has a mean of 30.8 words per min

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

According to the College Board, scores on the math section of the SAT Reasoning college entrance test for the class of 2010 had a mean of 516 and a standard deviation of 116. Assume that they are roughly normal.One of the quartiles of the scores from the math section of the SAT Reasoning test is 438. The other quartile is _______.
The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…
You are given the smaple mean and the population m standard deviation. Use this info to construct the 90% and 95% confidence intervals for the population mean. Interpert the results and compare the widths of the confidence intervals. A random sample of 50 home theater systems has a mean price of $145. Assume the population standard deviation is $17.30
A recent report claims that Americans spend an average of $11 per day on lunch. You believe that people who live in Philadelphia, PA spend significantly less on lunch per day than that. In order to test this, you randomly sampled n=100 Philadelphia residents and asked them how much they spend on lunch everyday. The sample average of these respondents was $10.92 with a sample standard deviation of $1.07. If you want to test the null hypothesis that H0: mean=11 vs Ha: mean <11.what is the value of the test statistic?
A group of transfer bound students wondered if they will spend the same mean amount on texts and supplies each year at their four-year university as they have at their community college. They conducted a random survey of 54 students at their community college and 66 students at their local four-year university. The sample means were $947 and $1,011, respectively. The population standard deviations are known to be $254 and $87, respectively. You are to conduct a hypothesis test to determine if the means are statistically the same using 5% as alpha What is the computed test statistic?
The Statistics Games are played by a large number of teams across the county. Teams raise money to cover expenses incurred by participating. You want to estimate the mean amount of money raised by teams. You take a random sample of 36 teams and find a mean of $375, with a standard deviation of $32. What critical value should you use for a 95% confidence interval?
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Suppose we wish to study the average income of Cactus Club customers, so we plan to conduct a research project with a 95% confidence level. We need our range of error (E) to be no greater than $500. Based on our past experience, we estimate the sample standard deviation to be $5,000. What sample size do you need in order to conduct the research? Select one: a. 372 b. 784 c. 824 d. 385 e. 196
A researcher would like to evaluate the effectiveness of a pain-relief patch designed for lower back pain. Prior to testing the patch, each of n = 8 patients rates the current level of back pain on a scale from 1 to 10. After wearing the patch for 90 minutes, a second pain rating is recorded. The data are as follows: Include in your responses: A. Compute the mean and variance for the sample of difference scores. B. Provide the Null and alternative hypotheses C. Calculate SSD
You want to know about the mean price of gas per gallon in all gas stations in Indiana. You are going to select 30 random gas stations from Indiana to estimate it. From now on, suppose that you do not know the population standard deviation. Therefore, you instead calculated the sample standard deviation, and it was $0.85. What is the margin of error for a 95% confidence interval for the population mean price of gas per gallon? Using the sample standard deviation value from Question 19 ($0.85), what is the 95% confidence interval if the sample mean price is $3.15? Do you think that the confidence interval will change if you knew that there are 1200 number of gas stations in total in Indiana? What is the reason?
Last year, the average amount that teams for the Statistics Games raised was $375. Have teams been more successful at fundraising this year? To find out, you take a random sample of 36 teams. Your sample of 36 teams yields a mean of $396 and a standard deviation of $70. Might you have made a Type 1 or Type 2 error? A Type 1. This means that we said that the mean amount raised had increased, when it was actually still $375. B You might have made a calculation error. C Neither- we're sure the average has increased. D Type 2. This would mean that we said there was not enough evidence to say the mean had increased from $375, when it actually is higher than $375. E Either kind is possible!
Determine if the following statements are true or false. a. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from the same population. Then, Mike’s sample mean will be closer to the true population mean than Jane’s sample. b. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from a population with mean and standard deviation 2. Then, the sample mean from Mike’s sample is more likely to be close to the true mean than the sample mean from Jane’s sample. That is, the probability that X is between 90% and 110% of mean is higher for Mike’s sample than for Jane’s sample.