We throw a coin until a head turns up for the second time, where p is the probability that a throw results in a head and we assume that the outcome of each throw is independent of the previous outcomes. Let X be the number of times we have thrown the coin. 1) Determine P(X 2), P(X = 3), and P(X = 4). 2) Show that P(X = n) = (n- 1) p (1 – p) 2 for n>= 2

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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We throw a coin until a head turns up for the second time, where p is the
probability that a throw results in a head and we assume that the outcome of each
throw is independent of the previous outcomes. Let X be the number of times we
have thrown the coin.
1) Determine P(X = 2), P(X = 3), and P(X = 4).
2) Show that P(X = n) = (n – 1) p (1 – p) 2 for n>= 2
n-2
Transcribed Image Text:We throw a coin until a head turns up for the second time, where p is the probability that a throw results in a head and we assume that the outcome of each throw is independent of the previous outcomes. Let X be the number of times we have thrown the coin. 1) Determine P(X = 2), P(X = 3), and P(X = 4). 2) Show that P(X = n) = (n – 1) p (1 – p) 2 for n>= 2 n-2
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