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We shall work with an RSA encryption exponent e that is a prime. For this application, the bigger e is, the more compression we get. Let Ie := {0, ..., e – 1}. Let n be an RSA modulus, generated as in Section 10.3 using an appropriate length parameter l. We also choose a random y e Z. The values e, n, and y are chosen once and for all, and together they determine a hash function Hrsa defined over (Z; × Ie, Z*) as follows: for a e Z;, and b e Ie, we define Hrsa (a, b) := a*y». Show that Hpsa is collision resistant under the RSA assumption.

We shall work with an RSA encryption exponent e that is a prime. For this application, the bigger e is, the more compression we get. Let Ie := {0, ..., e – 1}. Let n be an RSA modulus, generated as in Section 10.3 using an appropriate length parameter l. We also choose a random y e Z. The values e, n, and y are chosen once and for all, and together they determine a hash function Hrsa defined over (Z; × Ie, Z*) as follows: for a e Z;, and b e Ie, we define Hrsa (a, b) := a*y». Show that Hpsa is collision resistant under the RSA assumption.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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3. We shall work with an RSA encryption exponent e that is a prime. For this application, the bigger e is, the more compression we get. Let Ie as in Section 10.3 using an appropriate length parameter l. We also choose a random y e Z. The values e, n, and y are chosen once and for all, and together they determine a hash function Hrsa defined over (Z; × Ie, Z*) as follows: for a E Z, and b e le, we define {0, ..., e – 1}. Let n be an RSA modulus, generated Hrsa (a, b) := a°y". Show that Hrsa is collision resistant under the RSA assumption.
Transcribed Image Text:3. We shall work with an RSA encryption exponent e that is a prime. For this application, the bigger e is, the more compression we get. Let Ie as in Section 10.3 using an appropriate length parameter l. We also choose a random y e Z. The values e, n, and y are chosen once and for all, and together they determine a hash function Hrsa defined over (Z; × Ie, Z*) as follows: for a E Z, and b e le, we define {0, ..., e – 1}. Let n be an RSA modulus, generated Hrsa (a, b) := a°y". Show that Hrsa is collision resistant under the RSA assumption.
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