We need to minimize the cost (measured in units of $100,000) of the pipeline, C(x) = 20✔ 20 5 x + 10√x² +1. Step 3 We have C'(x) = -5 + Step 4 Solving 0 = C'(x) leads to 5√²+1 10x which can be re-written as x² + 1 = 4x² X = Step 6 10x Step 5 Therefore, since x must be non-negative, we have 1 Step 7 3 √x² + 1 Evaluate = 4( √5). ✓ 1 We must compare the costs for x = 0, √3' 10x √3 √(√) - (20 - ✓ E) √3 20 3 and 4. C(0) = 30 30 and C(4) = 10√17.

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Please help with the final quesion this is all the info i have and I am very stuck. there are two images

We need to minimize the cost (measured in units of $100,000) of the pipeline,
C(x) = 20✔
20
5 x + 10√x² +1.
Step 3
We have
C'(x) = -5 +
Step 4
Solving 0 = C'(x) leads to
5√²+1 10x
10x
which can be re-written as
x² + 1 = 4x²
X =
Step 6
√x² + 1
3
✓
Step 5
Therefore, since x must be non-negative, we have
1
√3
1
We must compare the costs for x = 0,
√3'
Step 7
Evaluate
= 4( √5).
( √5) - (20-5 15
3
10x
20 +
15
20
Step 8
Round your answer to two decimal places.
and 4. C(0) = 30
15
The minimum of these costs occurs when x = and so P should be
1
√3'
30 and C(4) = 10√17.
X km east of the refinery.
Transcribed Image Text:We need to minimize the cost (measured in units of $100,000) of the pipeline, C(x) = 20✔ 20 5 x + 10√x² +1. Step 3 We have C'(x) = -5 + Step 4 Solving 0 = C'(x) leads to 5√²+1 10x 10x which can be re-written as x² + 1 = 4x² X = Step 6 √x² + 1 3 ✓ Step 5 Therefore, since x must be non-negative, we have 1 √3 1 We must compare the costs for x = 0, √3' Step 7 Evaluate = 4( √5). ( √5) - (20-5 15 3 10x 20 + 15 20 Step 8 Round your answer to two decimal places. and 4. C(0) = 30 15 The minimum of these costs occurs when x = and so P should be 1 √3' 30 and C(4) = 10√17. X km east of the refinery.
An oil refinery is located on the north bank of a straight river that is 1 km wide. A pipeline is to be constructed from the refinery to storage tanks located on the south bank of the river 4 km east of the refinery. The cost of laying pipe is $500,000/km over land to a point P on the north bank
and $1,000,000/km under the river to the tanks. To minimize the cost of the pipeline, how far (in km) from the refinery should P be located?
Step 1
If x measures the distance from the point directly across the river from the storage tanks to the point P where the underwater pipe reaches the opposite shore, then there are m = 4-x
underwater.
refinery
m
P
1
storage tanks
-x
km of pipe over land and n =
+1
x² +1
km of pipe
Transcribed Image Text:An oil refinery is located on the north bank of a straight river that is 1 km wide. A pipeline is to be constructed from the refinery to storage tanks located on the south bank of the river 4 km east of the refinery. The cost of laying pipe is $500,000/km over land to a point P on the north bank and $1,000,000/km under the river to the tanks. To minimize the cost of the pipeline, how far (in km) from the refinery should P be located? Step 1 If x measures the distance from the point directly across the river from the storage tanks to the point P where the underwater pipe reaches the opposite shore, then there are m = 4-x underwater. refinery m P 1 storage tanks -x km of pipe over land and n = +1 x² +1 km of pipe
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