We must integrate y = (8x-x2)-(2x) = 6x-x². The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be (6x-x²) dx.
We must integrate y = (8x-x2)-(2x) = 6x-x². The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be (6x-x²) dx.
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![We must integrate y = (8x - x2) - (2x) = 6x-x².
The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be
(6x - x²) dx.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e97f32-5988-4deb-9547-eb6ce37eb1f3%2F0d35de28-aeee-4c1c-84a3-2cb03133b4a5%2Fopqavys_processed.png&w=3840&q=75)
Transcribed Image Text:We must integrate y = (8x - x2) - (2x) = 6x-x².
The limits on the integral correspond to the smallest and largest possible x-values where the two graphs intersect, and so will be
(6x - x²) dx.
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