We know that, in a monostable multi-vibrator, the application of trigger pulse gives a positive going pulse on the output. The same monostable multi-vibrator circuit can be used as a frequency divider. You have a signal (pulse), which varies between 0 and Vcc with a frequency of 4KHZ. Design circuits which will produce an output signal with, (a) 0.5X frequency (2KHZ) and (b) 0.25X frequency (1KHZ).

We know that, in a monostable multi-vibrator, the application of trigger pulse gives a positive going pulse on the output. The same monostable multi-vibrator circuit can be used as a frequency divider. You have a signal (pulse), which varies between 0 and Vcc with a frequency of 4KHZ. Design circuits which will produce an output signal with, (a) 0.5X frequency (2KHZ) and (b) 0.25X frequency (1KHZ).

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Use the following circuit to design an oscillator of 5 kHz output. The amplifier used in this oscillator is multistage C.S. with source resistance amplifier. The design must be with minimum No. of stages. Use the following FET parameters Id=2mA, gm=2.5 ms and rds = 40kN. Use VDD = 24V L R Vo Vi
Powered by ±10VIntegrator circuit designed with Op-AmpVin=3sin(2π400t) alternative signal to inputhas been applied. Analysis of output voltage (Vo)Draw the waveform.Calculate the maximum and rms value of out signal.
B. A step up chopper has a supply voltage of 250V while the output voltage is 500V. (a) Derive an equation for output voltage (b)If the period of the chopper be 100 μsec., determine the pulse width of the output voltage. (c) If the pulse width in (b) is reduced to one third for constant frequency operation, find the new output voltage.
Write about two applications for a series circuit, (Think about the different electronics at home or at work), and some of the advantages and disadvantages?
Design a buck converter such that the output voltage varies between from 20V to 28V while the input voltage is 40V. The maximum load power is 200Wde. Assume the switching frequency is 15kHz. (a) Design the converter such that it will be in continuous current mode. (b) The capacitor realized output voltage ripple must not be more than 1% at worst case. (c) The inductance realizes CCM at worst case. (d) Select the appropriate switch and other elements
A appropriate op-amp circuit with a gain of +100 is required for the ultrasonic device. Create a two-stage non-inverting op-amp circuit with Av = 10 for each stage. Provide calculation procedures that complement the circuit design.
3. Describe Amplitude Modulator as one of an OTA applications
Given the four statements, which of the following statements are true about an op-amp integrator? i. For an op-amp integrator wilh R = 10OKOhms, C = 10UF and a sine wave inpul waveform, the output waveform is a cosine waveform. %3D ii. For an op-amp integrator with R = 100KOhms, C = 10uF and a triangular input waveform, the output waveform is a square wave. iii. For an op-amp integrator with R- 100KOhms, C =10uF and a sine wave input waveform, the output waveform is a sawtooth waveform. v. For an op-amp integrator with R10OKOhms. C lCuF and a square wave input waveform, the output waveform is a triangular waveferm.
1st question
sketch the output waveform. show complete analysis.
Suppose a small AC voltage of amplitude .1Vpp is added to the input voltage of 5V What is the output AC voltage and the small signal voltage gain? Vin Lo VDD=10V R=10 Q2 Vout
An op-amp comparator in a firing circuit can produce waveforms at the output of up to 28 V peak-to-peak without any distortion. An inverse cosine-based firing circuit with a voltage range from +14 to -14 (reference voltage) is used to produce a gating signal for the SCR at the desired delay angle. if the reference voltage is 5.92 volts, the delay angle (in degrees) would be: