we know, Now, Senadu = enn fdu - (Sda Len) du [using product Rule] = x ln x - n. du = x ln x - n n In (+2)] dudy en (x+1) dudy + en (y+2) Ludy 0 0 0 0 = - 《(,)//༢༠) - (ཀ]a, +」「»(6)t], -2 (+1) + (en (4+2) dy = Silzenz = (2012-1)/dy dy + [(13 + 2) ln(+2) = (4+2)]' - = (2 in 2-1) [3] ' + [(3lms-3) - (2 m2-23] (1-0) + 3n3-3-2ln2+2 = (2n2-1) (1- = 2ln2-1+3 en 3-3-2 en 2 + 2 ་་ 3143-2
we know, Now, Senadu = enn fdu - (Sda Len) du [using product Rule] = x ln x - n. du = x ln x - n n In (+2)] dudy en (x+1) dudy + en (y+2) Ludy 0 0 0 0 = - 《(,)//༢༠) - (ཀ]a, +」「»(6)t], -2 (+1) + (en (4+2) dy = Silzenz = (2012-1)/dy dy + [(13 + 2) ln(+2) = (4+2)]' - = (2 in 2-1) [3] ' + [(3lms-3) - (2 m2-23] (1-0) + 3n3-3-2ln2+2 = (2n2-1) (1- = 2ln2-1+3 en 3-3-2 en 2 + 2 ་་ 3143-2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Where the +1 come from???
![we know,
Now,
Senadu = enn fdu - (Sda Len) du
[using product Rule]
=
x ln x
-
n. du
=
x ln x - n
n
In (+2)] dudy
en (x+1) dudy +
en (y+2) Ludy
0 0
0 0
=
- 《(,)//༢༠) - (ཀ]a, +」「»(6)t],
-2 (+1) + (en (4+2) dy
=
Silzenz
=
(2012-1)/dy
dy +
[(13 + 2) ln(+2) = (4+2)]'
-
= (2 in 2-1) [3] ' + [(3lms-3) - (2 m2-23]
(1-0) + 3n3-3-2ln2+2
=
(2n2-1) (1-
= 2ln2-1+3 en 3-3-2 en 2 + 2
་་
3143-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e53cf2c-4bf5-4ccd-bd0e-fb990a97eda5%2Fdb33ee71-0e51-412d-9f45-1499119e05ff%2F7cnutc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:we know,
Now,
Senadu = enn fdu - (Sda Len) du
[using product Rule]
=
x ln x
-
n. du
=
x ln x - n
n
In (+2)] dudy
en (x+1) dudy +
en (y+2) Ludy
0 0
0 0
=
- 《(,)//༢༠) - (ཀ]a, +」「»(6)t],
-2 (+1) + (en (4+2) dy
=
Silzenz
=
(2012-1)/dy
dy +
[(13 + 2) ln(+2) = (4+2)]'
-
= (2 in 2-1) [3] ' + [(3lms-3) - (2 m2-23]
(1-0) + 3n3-3-2ln2+2
=
(2n2-1) (1-
= 2ln2-1+3 en 3-3-2 en 2 + 2
་་
3143-2
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