we know, Now, Senadu = enn fdu - (Sda Len) du [using product Rule] = x ln x - n. du = x ln x - n n In (+2)] dudy en (x+1) dudy + en (y+2) Ludy 0 0 0 0 = - 《(,)//༢༠) - (ཀ]a, +」「»(6)t], -2 (+1) + (en (4+2) dy = Silzenz = (2012-1)/dy dy + [(13 + 2) ln(+2) = (4+2)]' - = (2 in 2-1) [3] ' + [(3lms-3) - (2 m2-23] (1-0) + 3n3-3-2ln2+2 = (2n2-1) (1- = 2ln2-1+3 en 3-3-2 en 2 + 2 ་་ 3143-2

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