We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT; :2XB AT¡ Afus Him If the activity of the solvent is given instead by aa = kA XA and the vapor pressures of the pure solvent and solute are P: and P, what is the new equation for ATf in terms of the mole fraction of solute? RT; "In kA Afus HĂm AT¡ = RT;2(In kA- XB) Afus HAm AT¡ = RT;2 In kA Afus HĂm AT¡ RT;²XAXB Afus HÂm Ο ΔΤ- RT;2(In ka-XB) ΔΤ Afus HAm RT;'XAXB Ο ΔΤ 2 fus HAm

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Chapter1: Chemical Foundations
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We have used Raoult's law to obtain the expression for the freezing point shift of a solution:
RT;²XB
Afus HAm
If the activity of the solvent is given instead by
aa = kĄ XA
and the vapor pressures of the pure solvent and solute are P and P, what is the new
equation for AT; in terms of the mole fraction of solute?
21n kA
O AT¡
RT;
Afus HAm
RT;2(In kA- XB)
Afus HAm
Ο ΔΤΙ
RT;² In kA
Afus HAm
2
ΔΤ
RT;²XẠXB
AT¡
Afus HAm
RT;2(In kA- XB)
O AT¡
fus HĂm
RT;²XAXB
AT¡ =
Afus HÂm
Transcribed Image Text:We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT;²XB Afus HAm If the activity of the solvent is given instead by aa = kĄ XA and the vapor pressures of the pure solvent and solute are P and P, what is the new equation for AT; in terms of the mole fraction of solute? 21n kA O AT¡ RT; Afus HAm RT;2(In kA- XB) Afus HAm Ο ΔΤΙ RT;² In kA Afus HAm 2 ΔΤ RT;²XẠXB AT¡ Afus HAm RT;2(In kA- XB) O AT¡ fus HĂm RT;²XAXB AT¡ = Afus HÂm
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