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We have rewritten the integral as follows. ee³x 2e3x dx We will now try to find some function u = g(x) in the integrand whose differential du = g'(x) dx also occurs, apart from a constant factor. e³x Here we notice that if we let u = e 2e3x [201²-13 ee³x dx = еч then du = x Jeu du X dx. Applying this substitution gives us the following.

We have rewritten the integral as follows. ee³x 2e3x dx We will now try to find some function u = g(x) in the integrand whose differential du = g'(x) dx also occurs, apart from a constant factor. e³x Here we notice that if we let u = e 2e3x [201²-13 ee³x dx = еч then du = x Jeu du X dx. Applying this substitution gives us the following.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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We have rewritten the integral as follows. /20³x 2e³x ee³x dx We will now try to find some function u = g(x) in the integrand whose differential du e3x 3x Here we notice that if we let u = e³x, then du = 3x 1 dx = √( 1 2e³x ee³x еч X Jeu du X = g'(x) dx also occurs, apart from a constant factor. ) dx. Applying this substitution gives us the following.
Transcribed Image Text:We have rewritten the integral as follows. /20³x 2e³x ee³x dx We will now try to find some function u = g(x) in the integrand whose differential du e3x 3x Here we notice that if we let u = e³x, then du = 3x 1 dx = √( 1 2e³x ee³x еч X Jeu du X = g'(x) dx also occurs, apart from a constant factor. ) dx. Applying this substitution gives us the following.
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