We have determined that g'(x) = 2 and h'(x) = cos(x), where g(x) = 2 In(x) and h(x) = sin(x). Applying the Chain Rule, gives the following result. F(x) = h(g(x)) F'(x) = h'(g(x)) · g'(x) 4 sin(In(x²)) – 2 cos(In(G²))
We have determined that g'(x) = 2 and h'(x) = cos(x), where g(x) = 2 In(x) and h(x) = sin(x). Applying the Chain Rule, gives the following result. F(x) = h(g(x)) F'(x) = h'(g(x)) · g'(x) 4 sin(In(x²)) – 2 cos(In(G²))
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![We have determined that g'(x) = 2 and h'(x) = cos(x), where g(x) = 2 In(x) and h(x) = sin(x). Applying the
Chain Rule, gives the following result.
F(x) = h(g(x))
F'(x) = h'(g(x)) · g'(x)
4 sin(In(x²)) – 2 cos(In(G²))](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e769afd-0b18-40cc-a2cc-648b66af3364%2F7bf4c8ee-1b07-45ae-a03c-396eaf9cc44a%2Fs50rwh_processed.png&w=3840&q=75)
Transcribed Image Text:We have determined that g'(x) = 2 and h'(x) = cos(x), where g(x) = 2 In(x) and h(x) = sin(x). Applying the
Chain Rule, gives the following result.
F(x) = h(g(x))
F'(x) = h'(g(x)) · g'(x)
4 sin(In(x²)) – 2 cos(In(G²))
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