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We have a function that is a power of t that is not equal to -1. Therefore, use the Powers of x (or t) Formula. 1 + C tn dt n + 1 Therefore, p(t) 1000t1.06 dt 1000 2.06 2.06 + C. 2.06 2.06 Step 2 1000 ,2.06 + C. We have p(t) 2.06 Since the current population is 100,000, p(0) = 1000 Therefore, determine the value of the arbitrary constant C and substitute this value for C in the equation. p(t) 1000 0,2.06 + C 2.06

We have a function that is a power of t that is not equal to -1. Therefore, use the Powers of x (or t) Formula. 1 + C tn dt n + 1 Therefore, p(t) 1000t1.06 dt 1000 2.06 2.06 + C. 2.06 2.06 Step 2 1000 ,2.06 + C. We have p(t) 2.06 Since the current population is 100,000, p(0) = 1000 Therefore, determine the value of the arbitrary constant C and substitute this value for C in the equation. p(t) 1000 0,2.06 + C 2.06

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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We have a function that is a power of t that is not equal to −1. Therefore, use the Powers of x (or t) Formula.

  tn dt
 
 
 = 
tn + 1
n + 1
 + C

Therefore,

p(t)  = 
  1000t1.06
 
 
 dt
We have a function that is a power of t that is not equal to -1. Therefore, use the Powers of x (or t) Formula. 1 + C tn dt n + 1 Therefore, p(t) 1000t1.06 dt 1000 2.06 2.06 + C. 2.06 2.06 Step 2 1000 ,2.06 + C. We have p(t) 2.06 Since the current population is 100,000, p(0) = 1000 Therefore, determine the value of the arbitrary constant C and substitute this value for C in the equation. p(t) 1000 0,2.06 + C 2.06
Transcribed Image Text:We have a function that is a power of t that is not equal to -1. Therefore, use the Powers of x (or t) Formula. 1 + C tn dt n + 1 Therefore, p(t) 1000t1.06 dt 1000 2.06 2.06 + C. 2.06 2.06 Step 2 1000 ,2.06 + C. We have p(t) 2.06 Since the current population is 100,000, p(0) = 1000 Therefore, determine the value of the arbitrary constant C and substitute this value for C in the equation. p(t) 1000 0,2.06 + C 2.06
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