We have a deck of 10 cards numbered from 1 to 10. Some are grey and some are white. The cards numbered 1, 7, and 9 are grey. 12 3 4 5 6 7 8 9 10 The cards numbered 2, 3, 4, 5, 6, 8, and 10 are white. A card is drawn at random. Let X be the event that the drawn card is grey, and let P(X) be the probability of X. Let not X be the event that the drawn card is not grey, and let P(not X) be the probability of not X. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the ever Outcomes Event Probability 123 4 5 6 7 8 9 10 O|口1□|□|□ P(x) = [] 口|ロ|□|C not X 口口|口|□|□|□|□|□|□1□ P(not X) = ] (b) Subtract. 1-P (not X) = ]

A First Course in Probability (10th Edition)
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ISBN:9780134753119
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p_u-IgNslkr7j8P3jH-IJiO2PjVHwzh28UxjbNS45rQ2WM6ERwj TRE3ZEKQ7CRXCTUD30MZE
O PROBABILITY
Probabilities of an event and its complement
We have a deck of 10 cards numbered from 1 to 10.
Some are grey and some are white.
The cards numbered 1, 7, and 9 are grey.
1 2 3 45 6 7 8 9 10
The cards numbered 2, 3, 4, 5, 6, 8, and 10 are white.
A card is drawn at random.
Let X be the event that the drawn card is grey, and let P(X) be the probability of X.
Let not X be the event that the drawn card is not grey, and let P(not X) be the probability of not X.
(a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event
Outcomes
Event
Probability
1
23 4 5 6 7 8 9 10
口|口|□|C10|□|□|□1□1□
P(x) = ]
口|口|口|□|□|□1□||□|□
P(not X) = ]
not X
(b) Subtract.
- P (not X) = []
Explanation
Check
O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use
Transcribed Image Text:p_u-IgNslkr7j8P3jH-IJiO2PjVHwzh28UxjbNS45rQ2WM6ERwj TRE3ZEKQ7CRXCTUD30MZE O PROBABILITY Probabilities of an event and its complement We have a deck of 10 cards numbered from 1 to 10. Some are grey and some are white. The cards numbered 1, 7, and 9 are grey. 1 2 3 45 6 7 8 9 10 The cards numbered 2, 3, 4, 5, 6, 8, and 10 are white. A card is drawn at random. Let X be the event that the drawn card is grey, and let P(X) be the probability of X. Let not X be the event that the drawn card is not grey, and let P(not X) be the probability of not X. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event Outcomes Event Probability 1 23 4 5 6 7 8 9 10 口|口|□|C10|□|□|□1□1□ P(x) = ] 口|口|口|□|□|□1□||□|□ P(not X) = ] not X (b) Subtract. - P (not X) = [] Explanation Check O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use
not X
P(not X) = ]
(b) Subtract.
1 – P(not X) = [.
(c) Select the answer that makes the sentence true.
1-P(not X) is the same as (Choose one)
Explanation
Check
62021 M
Olo
Transcribed Image Text:not X P(not X) = ] (b) Subtract. 1 – P(not X) = [. (c) Select the answer that makes the sentence true. 1-P(not X) is the same as (Choose one) Explanation Check 62021 M Olo
Expert Solution
Step 1

We have given that,

A deck of 10 cards numbered from 1 to 10. There are two colors one is grey and other one is white.

There are 3 grey color cards of numbered 1, 7 & 9.

And 7 white color cards of numbered 2, 3, 4, 5, 6, 8 & 10.

 

Let X be the event that the drawn card is grey and not X be the event that is not grey.

 

Probability = (Number of favourable cases) / ( Exhaustive cases )

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