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We have a 5 charge field the grid is 1 meter spacing and the charges are in Micro Coulombs. Ive atached two pictures of my work in solving for the force enacted on charge A for context. If added a 6th charge of (+10) at what location would we add it to make Fa = 0 ? and need to solve the value of DE ?     Location Charge(microcoulombs) A (0,0) -20 B (-2,+4) -10 C (-4,+2) +20 D (+1,+3,-5) -10 E (-3,-1,+2) -20

We have a 5 charge field the grid is 1 meter spacing and the charges are in Micro Coulombs. Ive atached two pictures of my work in solving for the force enacted on charge A for context. If added a 6th charge of (+10) at what location would we add it to make Fa = 0 ? and need to solve the value of DE ?     Location Charge(microcoulombs) A (0,0) -20 B (-2,+4) -10 C (-4,+2) +20 D (+1,+3,-5) -10 E (-3,-1,+2) -20

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We have a 5 charge field the grid is 1 meter spacing and the charges are in Micro Coulombs. Ive atached two pictures of my work in solving for the force enacted on charge A for context.

If added a 6th charge of (+10) at what location would we add it to make Fa = 0 ?

and need to solve the value of DE ?

 

  Location Charge(microcoulombs)
A (0,0) -20
B (-2,+4) -10
C (-4,+2) +20
D (+1,+3,-5) -10
E (-3,-1,+2) -20
Fa Causel by ab r Pec (-0.04i+0.161 + 0.08}-0.02) t o.08 Ĵ )N Fac=l0,16Î -0,08} Fad= (0.087î +0.26ĵ-o,434 R DN Fae=(-0,2061-0.069; +o.137 Ŕ)N Fab= (-0.04Î Fab+ Fac=(0. i2 %3D +Fac t Fad + Fae 二 Fa= (ou12î to.087î+0.26-o,434 ĥ-0.206î.. -0.069+0.137R) N =(0.001î +o91-0.297R)N (0.001, 0.191,-0, 297) + Rectangular Coordinates r=V(0.001)²+(0.191)?+(-0.297) =0.353 금) O= Arccos ( Z O= Arccos -0.297 =147.3° 0,353 $= Arctan / $ Arctan/O.i91)=89.7° O.001 (a353, 147.3°, 89.7°)+ Spherical Coordinates
Transcribed Image Text:Fa Causel by ab r Pec (-0.04i+0.161 + 0.08}-0.02) t o.08 Ĵ )N Fac=l0,16Î -0,08} Fad= (0.087î +0.26ĵ-o,434 R DN Fae=(-0,2061-0.069; +o.137 Ŕ)N Fab= (-0.04Î Fab+ Fac=(0. i2 %3D +Fac t Fad + Fae 二 Fa= (ou12î to.087î+0.26-o,434 ĥ-0.206î.. -0.069+0.137R) N =(0.001î +o91-0.297R)N (0.001, 0.191,-0, 297) + Rectangular Coordinates r=V(0.001)²+(0.191)?+(-0.297) =0.353 금) O= Arccos ( Z O= Arccos -0.297 =147.3° 0,353 $= Arctan / $ Arctan/O.i91)=89.7° O.001 (a353, 147.3°, 89.7°)+ Spherical Coordinates
|9x 108 Solve Fab Evaluate 20-10 ) (-10-101%) (-2)²+ 42) Eo.09 a) -2i+45\ simplify Evoluate 3) (0.09) (- \S(i-2;) -0.04021t0.0805N Solve Fac (9xi09)-20x10)(20 x10) =-0.18 ((-4)2+22) 2) (-4:+25 | (-0,18) =(0.16;-o.08 Solve Fad akiomp -20 x10) (-10 x10€) =0.0514 c)? +(3€ t (-S)? 2). (1.33 -Sk ) (oooSi4) ta0869; + 0. 2613-0.434 Ŕ )N Solve Fae 9x 107-20x10)-20x10e) =0.257 (-3)2+ (-ij2+ (2)2 2) -3; + -1j + +aK \ (0.257) =-0.2067-0.0687 j+o.137 K)N 1) 1) 1)
Transcribed Image Text:|9x 108 Solve Fab Evaluate 20-10 ) (-10-101%) (-2)²+ 42) Eo.09 a) -2i+45\ simplify Evoluate 3) (0.09) (- \S(i-2;) -0.04021t0.0805N Solve Fac (9xi09)-20x10)(20 x10) =-0.18 ((-4)2+22) 2) (-4:+25 | (-0,18) =(0.16;-o.08 Solve Fad akiomp -20 x10) (-10 x10€) =0.0514 c)? +(3€ t (-S)? 2). (1.33 -Sk ) (oooSi4) ta0869; + 0. 2613-0.434 Ŕ )N Solve Fae 9x 107-20x10)-20x10e) =0.257 (-3)2+ (-ij2+ (2)2 2) -3; + -1j + +aK \ (0.257) =-0.2067-0.0687 j+o.137 K)N 1) 1) 1)
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