We found two relationships between A and b. 7 = Ab 35 = Ab3 In order to solve for a variable, we need an equation that depends only on that variable. Obtain an equation that depends only on b by dividing the second relationship by the first. 35 Ab3 %3D Ab The fraction on the left-hand side can be reduced. Also, on the right-hand side there is an A in both the numerator and the denominator, so the A's cancel. Ab³ Ab In the numerator on the right-hand side we have b raised to the power denominator we have b raised to the power and in the Recall the rule of exponents for b > 0, bm = bm - n. Reduce the right-hand side using this rule. b2
We found two relationships between A and b. 7 = Ab 35 = Ab3 In order to solve for a variable, we need an equation that depends only on that variable. Obtain an equation that depends only on b by dividing the second relationship by the first. 35 Ab3 %3D Ab The fraction on the left-hand side can be reduced. Also, on the right-hand side there is an A in both the numerator and the denominator, so the A's cancel. Ab³ Ab In the numerator on the right-hand side we have b raised to the power denominator we have b raised to the power and in the Recall the rule of exponents for b > 0, bm = bm - n. Reduce the right-hand side using this rule. b2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:We found two relationships between A and b.
7 = Ab
35 =
Ab3
In order to solve for a variable, we need an equation that depends only on that variable. Obtain an equation
that depends only on b by dividing the second relationship by the first.
35
Ab3
%3D
Ab
The fraction on the left-hand side can be reduced. Also, on the right-hand side there is an A in both the
numerator and the denominator, so the A's cancel.
Ab3
Ab
In the numerator on the right-hand side we have b raised to the power
denominator we have b raised to the power
and in the
Recall the rule of exponents for b > 0,
bm
= bm - n. Reduce the right-hand side using this rule.
b2
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