We changed the first nonzero entry beneath the pivot to a zero and found the following augmented matrix. -1 1 1 45 0 33 90 1 010 Next we will change the other entry beneath the pivot to a zero. Formulate the Type 2 row operation that wll change the first entry in R, to a zero. Applying the row operation results in the following matrix. -1 1 1 45 0 3 90 2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 33RE
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We changed the first nonzero entry beneath the pivot to a zero and found the following augmented matrix.
-1 1 1 45
0 33 90
1 010
Next we will change the other entry beneath the pivot to a zero. Formulate the Type 2 row operation that will
change the first entry in R, to a zero.
R. ?vR,
Applying the row operation results in the following matrix.
-1 1
1
45
0 3
90
2
Transcribed Image Text:We changed the first nonzero entry beneath the pivot to a zero and found the following augmented matrix. -1 1 1 45 0 33 90 1 010 Next we will change the other entry beneath the pivot to a zero. Formulate the Type 2 row operation that will change the first entry in R, to a zero. R. ?vR, Applying the row operation results in the following matrix. -1 1 1 45 0 3 90 2
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