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We can now rewrite L{y} as follows. (금) . (공) Liy} S- 5 s+ 4 Next, to solve for y, we apply the inverse Laplace transform L-1 to each term. y(t) = L-3 + L- s + 4 We now recall the following, where a and b are constants. • By Theorem 7.2.1.: eat S - a • By linearity of L1: L-1{bs} = bL-1{s} Applying these gives the following result. y(t)

We can now rewrite L{y} as follows. (금) . (공) Liy} S- 5 s+ 4 Next, to solve for y, we apply the inverse Laplace transform L-1 to each term. y(t) = L-3 + L- s + 4 We now recall the following, where a and b are constants. • By Theorem 7.2.1.: eat S - a • By linearity of L1: L-1{bs} = bL-1{s} Applying these gives the following result. y(t)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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We can now rewrite L{y} as follows. (금). (금) 17 Liy} : S - 5 s+ 4 Next, to solve for y, we apply the inverse Laplace transform L-1 to each term. y(t) = L-1 + L-1 9 S - s + 4 We now recall the following, where a and b are constants. By Theorem 7.2.1.: 1 = eat S - a • By linearity of L1: L-!{bs} = bL-{s} Applying these gives the following result. y(t) =||
Transcribed Image Text:We can now rewrite L{y} as follows. (금). (금) 17 Liy} : S - 5 s+ 4 Next, to solve for y, we apply the inverse Laplace transform L-1 to each term. y(t) = L-1 + L-1 9 S - s + 4 We now recall the following, where a and b are constants. By Theorem 7.2.1.: 1 = eat S - a • By linearity of L1: L-!{bs} = bL-{s} Applying these gives the following result. y(t) =||
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