We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that the characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with a standard deviation of 3000 pounds. PLAN: We will estimate μ by giving a 99%99% confidence interval. SOLVE: Find the sample mean ?¯. (Enter your answer rounded to the nearest whole number.) ?¯= Give a 99%confidence interval, [low,high], for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) ???= ℎ??ℎ=
Unitary Method
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STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 44 inches long and 1.51.5 inches square? Given are data from students doing a laboratory exercise.
| 33,19033,190 | 31,86031,860 | 32,59032,590 | 26,52026,520 | 33,28033,280 |
| 32,32032,320 | 33,02033,020 | 32,03032,030 | 30,46030,460 | 32,70032,700 |
| 23,04023,040 | 30,93030,930 | 32,72032,720 | 33,65033,650 | 32,34032,340 |
| 24,05024,050 | 30,17030,170 | 31,30031,300 | 28,73028,730 | 31,92031,920 |
We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that the characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a
PLAN: We will estimate μ by giving a 99%99% confidence interval.
SOLVE: Find the sample
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