We are trying to prove the following limit. lim (6 - 2x) = -2 x→6 Once we have specified in terms of &, one of the steps in the proof is to show the following: If 0 < |□| < 8, then |□|<ɛ.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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We are trying to prove the following limit.
lim (6 - 2x)
x→6
= -2
Once we have specified in terms of &, one of the steps in the proof is to
show the following:
If 0 < |□| < 8, then ||< &.
Fill in the blanks (shown as square boxes) for this statement.
Transcribed Image Text:We are trying to prove the following limit. lim (6 - 2x) x→6 = -2 Once we have specified in terms of &, one of the steps in the proof is to show the following: If 0 < |□| < 8, then ||< &. Fill in the blanks (shown as square boxes) for this statement.
Expert Solution
Step 1: Given Information:

Given, 

              limit as x rightwards arrow 6 of left parenthesis 6 minus 2 x right parenthesis equals negative 6 space bold left parenthesis bold space bold italic n bold italic o bold italic t bold space bold minus bold 2 bold right parenthesis.

 To fill in the blanks for the following statement i.e.

          i f space 0 less than open vertical bar left square bracket space right square bracket close vertical bar less than delta comma space t h e n space open vertical bar left square bracket space right square bracket close vertical bar less than epsilon.


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