We are studying the octane number of two unleaded gasoline. Here is a table that summarizes the results of the study: Number Мean Standard Deviation Formula No 1 18 86.5 1.82 Formula No 2 44 84.6 1.01 a) Do the two formulas have the same dispersion? Use an a of risk of 10%. Critical Value: P Value: Check the box corresponding to the tested hypothesis: Ho: S1= S2 Ho: 0z= 02 O 2 H1: S1 # S2 Ho: 01= 02 H1: 0;<02 Ho: S1= S2 O 3 4 H1: S1< S2 Ho: 01= 02 H1: 0;>02 Ho: S1= S2 05 06 H1: S1 > S2 or None of the answers: On the basis of the observed results, we can conclude that .. I Both formulas have the same dispersion II The two formulas do not have the same dispersion b) Does formula # 1 have a higher octane number than formula # 2. Use a risk of a of 1%. Critical Value: P Value: Degree of Freedom: Check the box corresponding to the tested hypothesis:

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We are studying the octane number of two unleaded gasoline. Here is a table that summarizes the
results of the study:
Number
Мaan
Standard Deviation
Formula No 1
18
86.5
1.82
Formula No 2
44
84.6
1.01
a) Do the two formulas have the same dispersion? Use an a of risk of 10%.
Critical Value:
P Value:
Check the box corresponding to the tested hypothesis:
Ho: S1= S2
Ho: 01= 02
0 2
H1: S1 + S2
H1: 0,+ 02
Ho: 01= 02
H1: 0;<02
Ho: S1= S2
O3
H1: S1< S2
04
Ho: 01= 02
H1: 0,> 02
Ho: S1= S2
O5
H1: S1> S2
06
or None of the answers:
On the basis of the observed results, we can conclude that ..
I
Both formulas have the same dispersion
II
The two formulas do not have the same dispersion
b) Does formula # 1 have a higher octane number than formula # 2. Use a risk of a of 1%.
Critical Value:
P Value:
Degree of Freedom:
Check the box corresponding to the tested hypothesis:
Transcribed Image Text:We are studying the octane number of two unleaded gasoline. Here is a table that summarizes the results of the study: Number Мaan Standard Deviation Formula No 1 18 86.5 1.82 Formula No 2 44 84.6 1.01 a) Do the two formulas have the same dispersion? Use an a of risk of 10%. Critical Value: P Value: Check the box corresponding to the tested hypothesis: Ho: S1= S2 Ho: 01= 02 0 2 H1: S1 + S2 H1: 0,+ 02 Ho: 01= 02 H1: 0;<02 Ho: S1= S2 O3 H1: S1< S2 04 Ho: 01= 02 H1: 0,> 02 Ho: S1= S2 O5 H1: S1> S2 06 or None of the answers: On the basis of the observed results, we can conclude that .. I Both formulas have the same dispersion II The two formulas do not have the same dispersion b) Does formula # 1 have a higher octane number than formula # 2. Use a risk of a of 1%. Critical Value: P Value: Degree of Freedom: Check the box corresponding to the tested hypothesis:
H,:X, = X,
H;: X, + X,
O 1
Hoi H1= H2
O2
H;: µ, ± µ2
H,:X, =X,
Ho: H1= H2
H;: µ1 < µ2
0 4
H,: X, < X,
H,:X, = X, 05
H: X, > X,
Ho: H1= H2
H;: µj > µ2
06
or None of the answers:
On the basis of the observed results, we can conclude that:
I
Formula No 1 has a superior octane index
II
There is no significant difference between the formulas
III
Formula No 2 has a superior octane index
IV
No conclusion can be reached
Transcribed Image Text:H,:X, = X, H;: X, + X, O 1 Hoi H1= H2 O2 H;: µ, ± µ2 H,:X, =X, Ho: H1= H2 H;: µ1 < µ2 0 4 H,: X, < X, H,:X, = X, 05 H: X, > X, Ho: H1= H2 H;: µj > µ2 06 or None of the answers: On the basis of the observed results, we can conclude that: I Formula No 1 has a superior octane index II There is no significant difference between the formulas III Formula No 2 has a superior octane index IV No conclusion can be reached
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