We are standing on the top of a 768 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) = – 16ť² + 128t + 768. What is the highest point that the object reaches?

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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095 4.2 Quadratic Functions in Standard Form
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We are standing on the top of a 768 feet tall building and launch a small object upward. The object's
vertical position, measured in feet, after t seconds is h(t) = - 16t? + 128t + 768. What is the highest
point that the object reaches?
feet
Question Help: M Message instructor
Transcribed Image Text:095 4.2 Quadratic Functions in Standard Form Progress saved Done Score: 0.77/11 1/11 answered Question 9 く > C 0/1 pt 5 10 99 O Details We are standing on the top of a 768 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) = - 16t? + 128t + 768. What is the highest point that the object reaches? feet Question Help: M Message instructor
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