we are given this situation: snow is falling at a constant rate of 3/5 in per hour and is being removed at a constant rate of 45% of the amount of snow on the ground per hour. The height of snow as a function of time is h(t) where our initial condition is h(0)=4. Our differential equation would thus be dh/dt = 3/5 - (9/20)h. Solving this gives h(t)=4/3 + (8/3)e^(-(9/20)t). All of the snow cannot be removed under these conditions because we cannot solve for h(t)=0 because it is undefined. The lowest the snow can reach is about 4/3 inches. But how could we change the rate of snowfall and rate of snow removal so that h(t) could equal zero?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
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we are given this situation: snow is falling at a constant rate of 3/5 in per hour and is being removed at a constant rate of 45% of the amount of snow on the ground per hour. The height of snow as a function of time is h(t) where our initial condition is h(0)=4. Our differential equation would thus be dh/dt = 3/5 - (9/20)h. Solving this gives h(t)=4/3 + (8/3)e^(-(9/20)t). All of the snow cannot be removed under these conditions because we cannot solve for h(t)=0 because it is undefined. The lowest the snow can reach is about 4/3 inches. But how could we change the rate of snowfall and rate of snow removal so that h(t) could equal zero? 

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