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We are given the initial value y(0) = 2. Substituting this value and solving for L{y} gives the following result. sLy} - v(0) + 4Ly} S - 5 1 sL{Y} + 4L{y} S- 5 L{y}(s + 4) + S - 5 1. Liy} (s - 5)(s + 4) s+ 4 2s - L{y} (s - 5)(s + 4)

We are given the initial value y(0) = 2. Substituting this value and solving for L{y} gives the following result. sLy} - v(0) + 4Ly} S - 5 1 sL{Y} + 4L{y} S- 5 L{y}(s + 4) + S - 5 1. Liy} (s - 5)(s + 4) s+ 4 2s - L{y} (s - 5)(s + 4)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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We are given the initial value y(0) = 2. Substituting this value and solving for L{y} gives the following result. SLiy} - y(0) + 4L{y} S- 5 sL{y} + 4L{y} S- 5 Liy}(s + 4) S - 5 1 L{y} + (s - 5)(s + 4) s+ 4 2s Ly} (s 5)(s + 4)
Transcribed Image Text:We are given the initial value y(0) = 2. Substituting this value and solving for L{y} gives the following result. SLiy} - y(0) + 4L{y} S- 5 sL{y} + 4L{y} S- 5 Liy}(s + 4) S - 5 1 L{y} + (s - 5)(s + 4) s+ 4 2s Ly} (s 5)(s + 4)
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