We are given a mean of 3.55 gallons with a standard deviation of 6.09 gallons. Compute the number of standard deviations below the mean corresponding to0 gallons, rounding the result to three decimal places. 0 - 3.55 0 - mean standard deviation 6.09 -.5829 This tells us that zero gallons is x standard deviations below the mean.
We are given a mean of 3.55 gallons with a standard deviation of 6.09 gallons. Compute the number of standard deviations below the mean corresponding to0 gallons, rounding the result to three decimal places. 0 - 3.55 0 - mean standard deviation 6.09 -.5829 This tells us that zero gallons is x standard deviations below the mean.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
ch4 q21
![Tutorial Exercise
An article reported that the mean annual adult consumption of wine was 3.55 gallons and that the standard deviation was 6.09 gallons. Would
you use the empirical rule to approximate the proportion of adults who consume more than 9.64 gallons (1.e., the proportion of adults whose
consumption value exceeds the mean by more than 1 standard deviation)? Explain your reasoning.
Step 1
We are given a mean of 3.55 gallons with a standard deviation of 6.09 gallons. Compute the number of standard deviations below the mean
corresponding to 0 gallons, rounding the result to three decimal places.
0 - mean
0- 3.55
standard deviation
6.09
5829
This tells us that zero gallons is
x standard deviations below the mean.
Submit
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Transcribed Image Text:Tutorial Exercise
An article reported that the mean annual adult consumption of wine was 3.55 gallons and that the standard deviation was 6.09 gallons. Would
you use the empirical rule to approximate the proportion of adults who consume more than 9.64 gallons (1.e., the proportion of adults whose
consumption value exceeds the mean by more than 1 standard deviation)? Explain your reasoning.
Step 1
We are given a mean of 3.55 gallons with a standard deviation of 6.09 gallons. Compute the number of standard deviations below the mean
corresponding to 0 gallons, rounding the result to three decimal places.
0 - mean
0- 3.55
standard deviation
6.09
5829
This tells us that zero gallons is
x standard deviations below the mean.
Submit
Skip (you cannot come back)
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