Water with mass of 2 kg (initial temperature of water is 10-degree C) and ice with mass of 6 kg (initial temperature of ice is -10 degree C placed into insulated container. What is the mass of ice in the mixture at thermal equilibrium? water = 4200 J/(kg .K), Cice = 2100 J/(kg .K), L = 3.34×10 J/(kg)
Water with mass of 2 kg (initial temperature of water is 10-degree C) and ice with mass of 6 kg (initial temperature of ice is -10 degree C placed into insulated container. What is the mass of ice in the mixture at thermal equilibrium? water = 4200 J/(kg .K), Cice = 2100 J/(kg .K), L = 3.34×10 J/(kg)
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Transcribed Image Text:Water with mass of 2 kg (initial temperature of water is 10-degree C) and ice with mass of
6 kg (initial temperature of ice is -10 degree C placed into insulated container. What is the
mass of ice in the mixture at thermal equilibrium?
Cwater = 4200 J/(kg - K), Cice = 2100 J/(kg - K), L, = 3.34×10³ J/(kg)
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