Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is 1.70 ✕ 105 Pa and the pipe radius is 2.50 cm. At the higher point located at y = 2.50 m, the pressure is 1.23 ✕ 105 Pa and the pipe radius is 1.40 cm. (a) Find the speed of flow in the lower section. (b) Find the speed of flow in the upper section. (c) Find the volume flow rate through the pipe. ### Water Flow Through a Constricted PipeWater flows through a constricted pipe in steady, ideal flow. The conditions are as follows:- **Lower Point:** - Pressure: \( 1.70 \times 10^5 \) Pa - Pipe Radius: 2.50 cm- **Higher Point (at \( y = 2.50 \) m):** - Pressure: \( 1.23 \times 10^5 \) Pa - Pipe Radius: 1.40 cm#### Diagram Explanation:The diagram displays a curved pipe with two labeled points, \( P_1 \) and \( P_2 \), representing the lower and upper sections of the pipe, respectively. The vertical distance between these points is indicated as \( y \).#### Problems to Solve:(a) Calculate the speed of flow in the **lower section** of the pipe.\[\text{Speed in the lower section: } \_\_\_\_ \text{ m/s}\](b) Calculate the speed of flow in the **upper section** of the pipe.\[\text{Speed in the upper section: } \_\_\_\_ \text{ m/s}\](c) Calculate the volume flow rate through the pipe.\[\text{Volume flow rate: } \_\_\_\_ \text{ m}^3\text{/s}\]

Given: Pressure at lower point, P1=1.70×105 Pa Pressure at higher point, P2=1.23×105 Pa Radius of…

Answered: Water moves through a constricted pipe…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is 1.70 ✕ 10⁵ Pa and the pipe radius is 2.50 cm. At the higher point located at y = 2.50 m, the pressure is 1.23 ✕ 10⁵ Pa and the pipe radius is 1.40 cm. (a) Find the speed of flow in the lower section. (b) Find the speed of flow in the upper section. (c) Find the volume flow rate through the pipe.

### Water Flow Through a Constricted Pipe

Water flows through a constricted pipe in steady, ideal flow. The conditions are as follows:

- **Lower Point:**
- Pressure: \( 1.70 \times 10^5 \) Pa
- Pipe Radius: 2.50 cm

- **Higher Point (at \( y = 2.50 \) m):**
- Pressure: \( 1.23 \times 10^5 \) Pa
- Pipe Radius: 1.40 cm

#### Diagram Explanation:

The diagram displays a curved pipe with two labeled points, \( P_1 \) and \( P_2 \), representing the lower and upper sections of the pipe, respectively. The vertical distance between these points is indicated as \( y \).

#### Problems to Solve:

(a) Calculate the speed of flow in the **lower section** of the pipe.

\[
\text{Speed in the lower section: } \_\_\_\_ \text{ m/s}
\]

(b) Calculate the speed of flow in the **upper section** of the pipe.

\[
\text{Speed in the upper section: } \_\_\_\_ \text{ m/s}
\]

(c) Calculate the volume flow rate through the pipe.

\[
\text{Volume flow rate: } \_\_\_\_ \text{ m}^3\text{/s}
\]

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