Water is the working fluid in an ideal regenerative Rankine cycle with one closed feedwater heater. Steam enters the turbine at 1400 lb/in.2 and 1400°F and expands to 120 lb/in.2, where some of the steam is extracted and diverted to the closed feedwater heater. The remaining steam expands through the second-stage turbine to the condens pressure of 2 lb/in.² Condensate exiting the feedwater heater as saturated liquid at 120 lb/in.² undergoes a throttling process as it passes through a trap into the condenser. The feedwater leaves the heater at 1400 lb/in.² and a temperature equal to the saturation temperature at 120 lbf/in.² The net power output of the cycle is 298 MW.

Water is the working fluid in an ideal regenerative Rankine cycle with one closed feedwater heater. Steam enters the turbine at 1400 lb/in.2 and 1400°F and expands to 120 lb/in.2, where some of the steam is extracted and diverted to the closed feedwater heater. The remaining steam expands through the second-stage turbine to the condens pressure of 2 lb/in.² Condensate exiting the feedwater heater as saturated liquid at 120 lb/in.² undergoes a throttling process as it passes through a trap into the condenser. The feedwater leaves the heater at 1400 lb/in.² and a temperature equal to the saturation temperature at 120 lbf/in.² The net power output of the cycle is 298 MW.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The ___________ is whatever we want to study it may be simple as a free body as complex as an entire chemical relinery A. Heat B. Temperature C. System D. Voltage E. Thermodynamics 2. It states the ratio between the pressure-Volume product and absolute temperature of gas is a constant A. Charles Law B. Combined Gas Law C. Avogadros Law D. Boyles Law 3.The wood ________ refers to the condition of a system as described by it`s properties. Since these are normally relations among the properties of a system. It can be specified by providing the values of a subset of the properties. A. Close system B. Process C. Properly D. Open System E.State 4. A process that occur at constant temperature a.Isothermal Process b.Adiabatic process c.Isentropic process d.Isobaric process
Descriptive Question Identify Kelvin-Planck Statement for the Second Law of Thermodynamics. hp
20. What is the most probable value of universal gas constant? c. 15451lb-ft/lb-°R a. 8.3142kJ/kmol-K b. 15481b-ft/lbmol-°R d. 8.3195kJ/kmol-K
Which of the following are correct and valid for the Kelvin-Plank statement? O a. Any device O b. Kelvin- Planck O c. It is possible for any O d. No heat engine can have a thermal O e. Kelvin- Planck O f. It is impossible O g. It is impossible for any device O h. It is impossible that statement statement to construct to construct of the second law is device that a device that a device that violates of the efficiency of 100 second law is the that operates in a cycle and produces no effect other than Kelvin- operates in a cycle and produces no effect other than operates negative statement, and a operates on a cycle to receive heat from a single reservoir Planck percent, or as for a positive statement, and a positive on a cycle to receive heat statement power plant to operate, the working fluid also violates negative statement the from a statement the transfer the transfer single reservoir and Clausius cannot be can be of heat from and of heat from a lower- temperature body to a higher-…
Choose the correct answer only as soon as possible please
12. thermodynamics
The combustion chamber of a diesel power plant has a theoretical heat value of 102 K Joules in a 98 25% combustion efficiency. What is the actual heat released in the systern in BTU? 90.44 BTU 94.99 BTU 98.55 BTU 99.98 BTU
1. Give me three (3) problems with solutions each of the following: a) Elasticity b) Vibratory Motion c) Fluid Motion d) Temperature and Heat
A piston cylinder arrangement initially contains 7.0 kgs of super- heated steam at 500 kPa and 250 C, now heat is removed until 44% condenses. 1) What is the amount of heat removed in (kJ)? 13935.32 11152.41 10432.49 7472.29 8357.65 6817.34 Not listed 12703.96 • 9243.01 2) What is the final volume (m )? O0.8448 1.0018 1.6297 1.2634 1.7866 1.1588 1.3681 1.4727 Not listed
State if the listed statement is Ture (T) or False (F) and correct the false statement: 1. Thermodynamic is a science of energy 2. Closed system is also called control volume 3. Steam power plant cycle is employed to produce a mechanical and electrical energy 4. In a Carnot cycle, the isothermal process in a boiler and a condenser ( ) 5. Isobaric process means volume is constant 6. Isentropic process means adiabatic and reversible 7. Pump is a device that consumes energy 8. Compressor is a device that raises a pressure of incompressible fluid flow ( ) 9. Thermal efficiency means the output by input 10. Cycle means a group of process that has initial state and final state ( ) ( )
The previous Bartleby person that answered my questions BUT I dont understand were he got the answers from . I NEED HELP to replicate. I have ticked the parts I understood and been able to replicate. Given the table of results find the following. Give answers in KW. Please show all working out Rate of heat transfer to evaporator from the chilled water: Answer : 0.60KW ✓ Rate of heat transfer from condenser to the cooling water: Answer : 0.764KW ✓ Rate of heat transfer to refrigerant in “Evaporator” using enthalpy values: Answer: 1.5: I DON’T UNDERSTAND the answer given – see below Rate of heat transfer from refrigerant in “Condenser” using enthalpy values Work input from the compressor to the refrigerant using enthalpy values The previous Bartleby answer stated that at P1 =288 KPa and T1 =3.48 h1= 253.66 KJ/Kg P2 =823 KPa and T2 =65 h2= 301.48 KJ/Kg Given P3 =815 KPa and T3 =30.4 h3= 94.2 KJ/Kg (I don’t understand where the 94.2 comes from) P4 =294 KPa…
Thermo dynamic