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Water is supplied at 150 ft³/s and 61 psi to a hydraulic turbine through a 3-ft inside-diameter inlet pipe as indicated in the figure below. The turbine discharge pipe has a 4.1-ft inside diameter. The static pressure at section (2), 10 ft below the turbine inlet, is 10 in. Hg vacuum. If the turbine develops 2600 hp, determine the rate of loss of available energy between sections (1) and (2). Section (1). 10 ft power loss = P1 = 61psi Q=150ft/s D₁ = 3 ft Turbine. P₂ = 10 in. Hg vacuum D₂=4.1ft Section (2) hp

Water is supplied at 150 ft³/s and 61 psi to a hydraulic turbine through a 3-ft inside-diameter inlet pipe as indicated in the figure below. The turbine discharge pipe has a 4.1-ft inside diameter. The static pressure at section (2), 10 ft below the turbine inlet, is 10 in. Hg vacuum. If the turbine develops 2600 hp, determine the rate of loss of available energy between sections (1) and (2). Section (1). 10 ft power loss = P1 = 61psi Q=150ft/s D₁ = 3 ft Turbine. P₂ = 10 in. Hg vacuum D₂=4.1ft Section (2) hp

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Current Attempt in Progress Water is supplied at 150 ft3/s and 61 psi to a hydraulic turbine through a 3-ft inside-diameter inlet pipe as indicated in the figure below. The turbine discharge pipe has a 4.1-ft inside diameter. The static pressure at section (2), 10 ft below the turbine inlet, is 10 in. Hg vacuum. If the turbine develops 2600 hp, determine the rate of loss of available energy between sections (1) and (2). Section (1), 10 ft power loss = P₁ = 61psi Q=150ft³/s D₁ = 3 ft Turbine P₂ = 10 in. Hg. vacuum D₂=4.1ft Section (2) hp
Transcribed Image Text:Current Attempt in Progress Water is supplied at 150 ft3/s and 61 psi to a hydraulic turbine through a 3-ft inside-diameter inlet pipe as indicated in the figure below. The turbine discharge pipe has a 4.1-ft inside diameter. The static pressure at section (2), 10 ft below the turbine inlet, is 10 in. Hg vacuum. If the turbine develops 2600 hp, determine the rate of loss of available energy between sections (1) and (2). Section (1), 10 ft power loss = P₁ = 61psi Q=150ft³/s D₁ = 3 ft Turbine P₂ = 10 in. Hg. vacuum D₂=4.1ft Section (2) hp
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