Water is pumped from che large tank shown in the igure. The loss in the piping is equal to 2V2 - note that this oss is in units of m?/s? = J/kg. 4 m The pump power is Wpur 40,000 Q – 400,000Q³, where Wump is in Watts and Q s in m³/s a.) Determine the flowrate. p.) Determine the pressure increase across the %3D dшnd, Pump ритр Pipe area = 0.01 m? pump ) Determine the flowrate if the loss was the same but the nump is not installed
Water is pumped from che large tank shown in the igure. The loss in the piping is equal to 2V2 - note that this oss is in units of m?/s? = J/kg. 4 m The pump power is Wpur 40,000 Q – 400,000Q³, where Wump is in Watts and Q s in m³/s a.) Determine the flowrate. p.) Determine the pressure increase across the %3D dшnd, Pump ритр Pipe area = 0.01 m? pump ) Determine the flowrate if the loss was the same but the nump is not installed
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:Water is pumped from the large tank shown in the figure. The loss in the piping is equal to 2V² – note that this loss is in units of m²/s² = J/kg. The pump power is \( \dot{W}_{pump} = 40,000 \, Q - 400,000 Q^3 \), where \( \dot{W}_{pump} \) is in Watts and Q is in m³/s.
a.) Determine the flow rate.
b.) Determine the pressure increase across the pump.
c.) Determine the flow rate if the loss was the same, but the pump is not installed.
**Diagram Explanation:**
- The diagram shows a large tank with water at a certain level.
- Water is drawn from the bottom of this tank and moves through a pipe with an area of 0.01 m².
- The pipe has a pump to assist in moving the water.
- The height from the water surface in the tank to the pipe inlet is labeled as 4 meters.
- Arrows indicate the direction of water flow, and the symbol Q represents the flow rate.
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