Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P₁ = 20 atm, Z₁ = 0 m, P₂ = 2 atm, and Z2 = 100 m. The density of water is 1000 kg/m³ and the viscosity is 0.001 kg/(m-sec). Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop AP = 2fLv2/D (kPa). The friction factor f is given by the Colebrook equation as follows: ε 1.255 1 -1.7372 In + (3.7D NRe√f) Answer: inlet volumetric flowrate = 0.0610367 m³/sec pressure drop due to friction loss = 849.219 kPa
Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P₁ = 20 atm, Z₁ = 0 m, P₂ = 2 atm, and Z2 = 100 m. The density of water is 1000 kg/m³ and the viscosity is 0.001 kg/(m-sec). Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop AP = 2fLv2/D (kPa). The friction factor f is given by the Colebrook equation as follows: ε 1.255 1 -1.7372 In + (3.7D NRe√f) Answer: inlet volumetric flowrate = 0.0610367 m³/sec pressure drop due to friction loss = 849.219 kPa
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The
inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the
roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 =
2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec).
Calculate the inlet volumetric flow rate (m³/sec) and the pressure drop APf
%3D
2fLv? /D (kPa).
The friction factor f is given by the Colebrook equation as follows:
1.255
1
-1.7372 In
3.7D NReVf,
Answer:
inlet volumetric flowrate = 0.0610367 m³/sec
pressure drop due to friction loss = 849.219 kPa
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