Water flows out of a spigot at the bottom of a very wide storage tank at a velocity of 10.4 m/s? What is the depth of this storage tank?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
**Problem Statement:**

Water flows out of a spigot at the bottom of a very wide storage tank at a velocity of 10.4 m/s. What is the depth of this storage tank?

**Analysis:**

In fluid dynamics, the velocity of fluid flowing out of an opening can be related to the depth of the fluid above the opening using Torricelli’s Law. This states that the speed \( v \) of efflux is given by:

\[ v = \sqrt{2gh} \]

where:
- \( v \) is the exit velocity (10.4 m/s in this case),
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on Earth),
- \( h \) is the height (or depth) of the fluid above the opening.

**Solution:**

Rearrange the formula to solve for \( h \):

\[ h = \frac{v^2}{2g} \]

Substitute the known values:

\[ h = \frac{(10.4)^2}{2 \times 9.81} \]

\[ h = \frac{108.16}{19.62} \]

\[ h \approx 5.51 \, \text{meters} \]

Therefore, the depth of the storage tank is approximately 5.51 meters.
Transcribed Image Text:**Problem Statement:** Water flows out of a spigot at the bottom of a very wide storage tank at a velocity of 10.4 m/s. What is the depth of this storage tank? **Analysis:** In fluid dynamics, the velocity of fluid flowing out of an opening can be related to the depth of the fluid above the opening using Torricelli’s Law. This states that the speed \( v \) of efflux is given by: \[ v = \sqrt{2gh} \] where: - \( v \) is the exit velocity (10.4 m/s in this case), - \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on Earth), - \( h \) is the height (or depth) of the fluid above the opening. **Solution:** Rearrange the formula to solve for \( h \): \[ h = \frac{v^2}{2g} \] Substitute the known values: \[ h = \frac{(10.4)^2}{2 \times 9.81} \] \[ h = \frac{108.16}{19.62} \] \[ h \approx 5.51 \, \text{meters} \] Therefore, the depth of the storage tank is approximately 5.51 meters.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Density of fluid
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON