Water at 25°C is pumped at 1800 gal/min from the lower to upper reservoir, as shown in Figure below (Zı = 30 ft and z2 = 180 ft). Pipe friction losses are approximated by h = 35V/2g, where V is the average velocity in the pipe. The pump is 80% efficient. (a) Find the head loss due to friction, h in ft. (b) Compute the pump head, h, in ft and the pump power needed, Ppump in horse power (hp). %3D Given: Specific weight of water, ywater= 62.4 lb/ft; 1 ft'/s = 448.8 gal/min. Show all calculations. Z2 = 180 ft z1 = 30 ft D= 6 in Pump
Water at 25°C is pumped at 1800 gal/min from the lower to upper reservoir, as shown in Figure below (Zı = 30 ft and z2 = 180 ft). Pipe friction losses are approximated by h = 35V/2g, where V is the average velocity in the pipe. The pump is 80% efficient. (a) Find the head loss due to friction, h in ft. (b) Compute the pump head, h, in ft and the pump power needed, Ppump in horse power (hp). %3D Given: Specific weight of water, ywater= 62.4 lb/ft; 1 ft'/s = 448.8 gal/min. Show all calculations. Z2 = 180 ft z1 = 30 ft D= 6 in Pump
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Pumping System Analysis**
**Problem Statement:**
Water at 25°C is pumped at 1800 gal/min from the lower to upper reservoir, as shown in the figure below (\(z_1 = 30\) ft and \(z_2 = 180\) ft). Pipe friction losses are approximated by
\[ h_f = 35 \frac{V^2}{2g} \]
where \(V\) is the average velocity in the pipe. The pump is 80% efficient.
**Tasks:**
(a) Find the head loss due to friction, \(h_f\), in ft.
(b) Compute the pump head, \(h_p\) in ft, and the pump power needed, \(P_{\text{pump}}\) in horsepower (hp).
**Given:**
- Specific weight of water, \(\gamma_{\text{water}} = 62.4 \, \text{lb}_f/\text{ft}^3\)
- Conversion: \(1 \, \text{ft}^3/\text{s} = 448.8 \, \text{gal/min}\)
**Instructions:**
Show all calculations.
**Diagram Description:**
The diagram shows a system with two reservoirs connected by a pipe and a pump. The lower reservoir is at elevation \(z_1 = 30\) ft, and the upper reservoir is at elevation \(z_2 = 180\) ft. The pipe has a diameter \(D = 6\) inches and conveys water from the lower to the upper reservoir using a pump. The direction of flow is indicated by arrows.
**Note:** The pump is depicted between the two reservoirs to elevate water to a higher elevation, overcoming gravitational and frictional losses.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4a02593-47b6-4253-beb0-7c85972c9833%2Feddd1b34-a97c-43e5-bc56-b865568685f9%2Fjuhy2qp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Pumping System Analysis**
**Problem Statement:**
Water at 25°C is pumped at 1800 gal/min from the lower to upper reservoir, as shown in the figure below (\(z_1 = 30\) ft and \(z_2 = 180\) ft). Pipe friction losses are approximated by
\[ h_f = 35 \frac{V^2}{2g} \]
where \(V\) is the average velocity in the pipe. The pump is 80% efficient.
**Tasks:**
(a) Find the head loss due to friction, \(h_f\), in ft.
(b) Compute the pump head, \(h_p\) in ft, and the pump power needed, \(P_{\text{pump}}\) in horsepower (hp).
**Given:**
- Specific weight of water, \(\gamma_{\text{water}} = 62.4 \, \text{lb}_f/\text{ft}^3\)
- Conversion: \(1 \, \text{ft}^3/\text{s} = 448.8 \, \text{gal/min}\)
**Instructions:**
Show all calculations.
**Diagram Description:**
The diagram shows a system with two reservoirs connected by a pipe and a pump. The lower reservoir is at elevation \(z_1 = 30\) ft, and the upper reservoir is at elevation \(z_2 = 180\) ft. The pipe has a diameter \(D = 6\) inches and conveys water from the lower to the upper reservoir using a pump. The direction of flow is indicated by arrows.
**Note:** The pump is depicted between the two reservoirs to elevate water to a higher elevation, overcoming gravitational and frictional losses.
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