### Problem StatementWater at 10°C flows through the system shown in the figure below at 0.40 m³/s. Energy loss in the 40-cm pipe is negligible. Energy loss in the 30-cm pipe is known to be \(1.5V^2\). A mercury manometer indicates that the absolute pressure at the top of the 30-cm pipe is 749.5 mm Hg abs. The pressure of the surroundings is 101,330 Pa. Calculate the power input to the pump.### Diagram Explanation- **Water Source**: The water has a temperature of 10°C.- **Pipe System**: - The initial pipe has a diameter of 40 cm and an elevation of 6 m. - This 40-cm diamter pipe connects to a 30-cm diameter pipe with an elevation of 10 m. - The outlet has an elevation of 2 m.- **Pressure and Elevation**: - The pressure at the top of the 30-cm pipe is given as 749.5 mm Hg. - Elevations are marked to show the vertical distance from a reference point, affecting the hydraulic calculations.### Calculation RequirementYou are required to determine the power input to the pump, denoted by \( \dot{W} \), in kilowatts (kW).### Parameters- Flow Rate: 0.40 m³/s- Absolute Pressure: 749.5 mm Hg- Surrounding Pressure: 101,330 Pa- Energy Loss in 30-cm Pipe: \(1.5V^2\)### Final NoteThis problem involves applying principles of fluid mechanics to find the necessary power input for the system, considering the given flow and pressure conditions. Remember to convert all units appropriately as you solve for the required power.

Given data: Q=0.4 m3/sD=40 cm=0.4 md=30 cm=0.3 mhL=1.5V2P1=101330 PaP2=749.5 mmHg133.32 Pa1…

Water at 10°C flows through the system shown in the figure below at 0.40 m/s. Energy loss in the 40-cm pipe is negligible. Energy loss in the 30-cm pipe is known to be 1.5V. A mercury manometer indicates that the absolute pressure at the top of the 30-cm pipe is 749.5 mm Hg abs. The pressure of the surroundings is 101,330 Pa. Calculate the power input to the pump. 740

Water at 10°C flows through the system shown in the figure below at 0.40 m/s. Energy loss in the 40-cm pipe is negligible. Energy loss in the 30-cm pipe is known to be 1.5V. A mercury manometer indicates that the absolute pressure at the top of the 30-cm pipe is 749.5 mm Hg abs. The pressure of the surroundings is 101,330 Pa. Calculate the power input to the pump. 740

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a vehicle. It can also be used in ship design to increase the speed at which ships pass through water.

Question

### Problem Statement

Water at 10°C flows through the system shown in the figure below at 0.40 m³/s. Energy loss in the 40-cm pipe is negligible. Energy loss in the 30-cm pipe is known to be \(1.5V^2\). A mercury manometer indicates that the absolute pressure at the top of the 30-cm pipe is 749.5 mm Hg abs. The pressure of the surroundings is 101,330 Pa. Calculate the power input to the pump.

### Diagram Explanation

- **Water Source**: The water has a temperature of 10°C.
- **Pipe System**:
- The initial pipe has a diameter of 40 cm and an elevation of 6 m.
- This 40-cm diamter pipe connects to a 30-cm diameter pipe with an elevation of 10 m.
- The outlet has an elevation of 2 m.

- **Pressure and Elevation**:
- The pressure at the top of the 30-cm pipe is given as 749.5 mm Hg.
- Elevations are marked to show the vertical distance from a reference point, affecting the hydraulic calculations.

### Calculation Requirement

You are required to determine the power input to the pump, denoted by \( \dot{W} \), in kilowatts (kW).

### Parameters

- Flow Rate: 0.40 m³/s
- Absolute Pressure: 749.5 mm Hg
- Surrounding Pressure: 101,330 Pa
- Energy Loss in 30-cm Pipe: \(1.5V^2\)

### Final Note

This problem involves applying principles of fluid mechanics to find the necessary power input for the system, considering the given flow and pressure conditions. Remember to convert all units appropriately as you solve for the required power.

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