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Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that th population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less th 2.79? Use the a=0.05 level of significance. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. Hoo (Choose one) ▼ H₁:0 (Choose one) This hypothesis test is a (Choose one) test. Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a=0.05, the critical value is X X

Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that th population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less th 2.79? Use the a=0.05 level of significance. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. Hoo (Choose one) ▼ H₁:0 (Choose one) This hypothesis test is a (Choose one) test. Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a=0.05, the critical value is X X

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Watching TV:** The 2012 General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that the population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less than 2.79? Use the α = 0.05 level of significance. --- **Part: 0 / 5** Progress Bar: A progress bar indicating 0 out of 5 parts completed. **Part 1 of 5** **State the appropriate null and alternate hypotheses.** \( H_0 : \sigma \) [Choose one] \( H_1 : \sigma \) [Choose one] This hypothesis test is a [Choose one] test. --- **Part: 1 / 5** Progress Bar: A progress bar indicating 1 out of 5 parts completed. **Part 2 of 5** **Find the critical value. Round the answer to three decimal places.** For α = 0.05, the critical value is [Text Box]. [Buttons: X, Reset] --- (Note: The text within brackets [ ] indicates fields where users can interact or input data.)
Transcribed Image Text:**Watching TV:** The 2012 General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that the population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less than 2.79? Use the α = 0.05 level of significance. --- **Part: 0 / 5** Progress Bar: A progress bar indicating 0 out of 5 parts completed. **Part 1 of 5** **State the appropriate null and alternate hypotheses.** \( H_0 : \sigma \) [Choose one] \( H_1 : \sigma \) [Choose one] This hypothesis test is a [Choose one] test. --- **Part: 1 / 5** Progress Bar: A progress bar indicating 1 out of 5 parts completed. **Part 2 of 5** **Find the critical value. Round the answer to three decimal places.** For α = 0.05, the critical value is [Text Box]. [Buttons: X, Reset] --- (Note: The text within brackets [ ] indicates fields where users can interact or input data.)
## Statistical Analysis Steps ### Step 1: Compute the Test Statistic - Compute the test statistic \( \chi^2 \). - Round the answer to three decimal places. **Input field** for calculation. --- ### Progress Bar - **Part: 3 / 5** - Graph: Progress is visually shown on a bar with 60% completion marked in blue and remaining sections in gray. --- ### Step 2: Hypothesis Testing - **Part 4 of 5** - **Determine whether to reject \( H_0 \):** - At the \( \alpha = 0.05 \) level, - **Dropdown menu**: Choose an option to either reject or not reject the null hypothesis \( H_0 \). **Input field** for decision. --- ### Step 3: State a Conclusion - **Part 5 of 5** - **Conclusion**: - Choose whether there is or isn’t enough evidence to conclude that the population standard deviation of TV watching times for teenagers is less than 2.79 hours. - **Dropdown menu** for selection. **Input field** for conclusion. ---
Transcribed Image Text:## Statistical Analysis Steps ### Step 1: Compute the Test Statistic - Compute the test statistic \( \chi^2 \). - Round the answer to three decimal places. **Input field** for calculation. --- ### Progress Bar - **Part: 3 / 5** - Graph: Progress is visually shown on a bar with 60% completion marked in blue and remaining sections in gray. --- ### Step 2: Hypothesis Testing - **Part 4 of 5** - **Determine whether to reject \( H_0 \):** - At the \( \alpha = 0.05 \) level, - **Dropdown menu**: Choose an option to either reject or not reject the null hypothesis \( H_0 \). **Input field** for decision. --- ### Step 3: State a Conclusion - **Part 5 of 5** - **Conclusion**: - Choose whether there is or isn’t enough evidence to conclude that the population standard deviation of TV watching times for teenagers is less than 2.79 hours. - **Dropdown menu** for selection. **Input field** for conclusion. ---
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