Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that th population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less th 2.79? Use the a=0.05 level of significance. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. Hoo (Choose one) ▼ H₁:0 (Choose one) This hypothesis test is a (Choose one) test. Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a=0.05, the critical value is X X

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Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that th
population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less tha
2.79? Use the a=0.05 level of significance.
Part: 0 / 5
Part 1 of 5
State the appropriate null and alternate hypotheses.
Hoo (Choose one)
H₁:
This hypothesis test is a (Choose one) test.
:0 (Choose one)
Part: 1 / 5
Part 2 of 5
Find the critical value. Round the answer to three decimal places.
For a=0.05, the critical value is
X
X
Ś
Ś
Transcribed Image Text:Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.09 with a standard deviation of 2.79. Assume that in a sample of 46 teenagers, the sample standard deviation of daily TV time is 2.6 hours, and that th population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is less tha 2.79? Use the a=0.05 level of significance. Part: 0 / 5 Part 1 of 5 State the appropriate null and alternate hypotheses. Hoo (Choose one) H₁: This hypothesis test is a (Choose one) test. :0 (Choose one) Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a=0.05, the critical value is X X Ś Ś
Compute the test statistic. Round the answer to three decimal places.
2
x² =
Part: 3 / 5
Part 4 of 5
Determine whether to reject Ho.
At the a=0.05 level, (Choose one)
Part: 4 / 5
X
Part 5 of 5
State a conclusion.
Ś
the null hypothesis Ho.
X
Ś
There (Choose one)
enough evidence to conclude that the population standard deviation of TV watching times for
teenagers is less than 2.79 hours.
X
Ś
Transcribed Image Text:Compute the test statistic. Round the answer to three decimal places. 2 x² = Part: 3 / 5 Part 4 of 5 Determine whether to reject Ho. At the a=0.05 level, (Choose one) Part: 4 / 5 X Part 5 of 5 State a conclusion. Ś the null hypothesis Ho. X Ś There (Choose one) enough evidence to conclude that the population standard deviation of TV watching times for teenagers is less than 2.79 hours. X Ś
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