A student was asked to find a 98% confidenceinterval for widget width using data from a randomsample of size n = 26. Which of the following is acorrect interpretation of the interval 14.3 < µ < 28.9?O There is a 98% chance that the mean of asample of 26 widgets will be between 14.3 and28.9.With 98% confidence, the mean width of allwidgets is between 14.3 and 28.9.O There is a 98% chance that the width of thewidget is between 14.3 and 28.9.O The width of all widgets is between 14.3 and28.9, 98% of the time. We know this is truebecause the mean of our sample is between14.3 and 28.9.With 98% confidence, the width of a randomlyselected widget will be between 14.3 and28.9.

ACCORDING TO GIVEN QUESTION WE HAVE ;- 98% confidence interval for widget width is 14.3<μ <…

Answered: was ask ed to a 98% conti nce interval…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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was ask ed to a 98% conti nce interval for widget width using data from a random sample of size n = 26. Which of the following is a correct interpretation of the interval 14.3 < µ< 28.9? A There is a 98% chance that the mean of a sample of 26 widgets will be between 14.3 and 28.9.