Would finding the sample mean weight to be 2.18 ounces provide strong evidence to doubt the manufacturer's claim that u = 2.20 ounces? Explain, again referring to the sampling distribution and a probability calculation. The probability of the sample weight being as small as 2.18 ounces or smaller is ___ (round to 4 decimal places)
Would finding the sample mean weight to be 2.18 ounces provide strong evidence to doubt the manufacturer's claim that u = 2.20 ounces? Explain, again referring to the sampling distribution and a probability calculation. The probability of the sample weight being as small as 2.18 ounces or smaller is ___ (round to 4 decimal places)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Would finding the sample
The probability of the sample weight being as small as 2.18 ounces or smaller is ___ (round to 4 decimal places)
![Candy Bar Weights
Assume that the actual weight of a certain candy bar varies according to a normal
distribution with mean μ = 2.20 ounces and standard deviation = 0.04
ounces. Suppose you are skeptical about the manufacturer's claim that the mean
weight is μ = 2.20 ounces, so you take a random sample of n = 5 candy bars and
weigh them. You find a sample mean weight of 2.16 ounces.
a. What does the CLT say about the distribution of sample mean weights if samples
of size n = 5 are taken repeatedly? Round your answer to FOUR decimal places, if
necessary.
The CLT predicts the sampling distribution of the sample mean will also be normally
distributed with mean___ and standard deviation](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F262813c4-301a-4a1d-9460-34c57760d32c%2Ffa0f1f45-d50b-407f-a640-ed52f4da6310%2Fq065v7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Candy Bar Weights
Assume that the actual weight of a certain candy bar varies according to a normal
distribution with mean μ = 2.20 ounces and standard deviation = 0.04
ounces. Suppose you are skeptical about the manufacturer's claim that the mean
weight is μ = 2.20 ounces, so you take a random sample of n = 5 candy bars and
weigh them. You find a sample mean weight of 2.16 ounces.
a. What does the CLT say about the distribution of sample mean weights if samples
of size n = 5 are taken repeatedly? Round your answer to FOUR decimal places, if
necessary.
The CLT predicts the sampling distribution of the sample mean will also be normally
distributed with mean___ and standard deviation
![b. Is it possible to get a sample mean weight this low even if the manufacturer's claim
that μ = 2.20 ounces is valid? Is it unlikely?
If the manufacturer's claim that μ = 2.20 ounces is true, the probability of
obtaining a random sample of five candy bars with a mean weight as small as 2.16
ounces or smaller is___ (round your answer to FOUR decimal places).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F262813c4-301a-4a1d-9460-34c57760d32c%2Ffa0f1f45-d50b-407f-a640-ed52f4da6310%2Ffmvlsgf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:b. Is it possible to get a sample mean weight this low even if the manufacturer's claim
that μ = 2.20 ounces is valid? Is it unlikely?
If the manufacturer's claim that μ = 2.20 ounces is true, the probability of
obtaining a random sample of five candy bars with a mean weight as small as 2.16
ounces or smaller is___ (round your answer to FOUR decimal places).
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Hello,
I want to know where did you get the 0.0127 , and 0.1318 probability from?
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