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F(A,B,C, D,E) =E ml0,1;3,6,8,9,14,ky1319,25,2931) DE 61 10 60 00 61 10

Q/Complete the following code in Python language (biometrics) for voice recognition and apply the code, mentioning the approved source if it exists import osimport numpy as npfrom pyAudioAnalysis import audioBasicIO, audioFeatureExtraction, audioTrainTestfrom pydub import AudioSegment# Function to capture and save voice samplesdef capture_voice_samples(num_samples, speaker_name):os.makedirs("speakers", exist_ok=True)os.makedirs(f"speakers/{speaker_name}", exist_ok=True)for i in range(num_samples):input(f"Press Enter and start speaking for sample {i + 1}...")# Recording audio using pyAudioAnalysisaudio = audioBasicIO.record_audio(4, 44100)filepath = f"speakers/{speaker_name}/sample_{i + 1}.wav"audioBasicIO.write_audio_file(filepath, audio, 44100)print(f"Sample {i + 1} saved for {speaker_name}")# Function to extract features from voice samplesdef extract_features():speakers = [d for d in os.listdir("speakers") if os.path.isdir(os.path.join("speakers", d))]all_features = []all_labels =…

T The information in DNA is stored as a code made up of four chemical bases which are represented by four upper case letters A, T, G, C. An example DNA sequence could be: ATGAG An interesting phenomena here is that when two DNA sequences are attempted to combine, A can only pair with T whereas G can only pair with C. Two DNA sequences for example ATGC and TACG are considered 'fully complementary' because the bases (letters) in every index position can be paired to each other (see the image). ATGC ATGC ATGC XX TACG Fully Complementary TACC SNP TTCA CA Non Complementary Two DNA sequences for example ATGC and TACC are considered 'SNP type' because there is exactly one index position (last position in this case) in which the bases(letters) can not be paired. Two DNA sequences for example ATGC and TTCA are considered "non complementary' because there are more than one index position (second and fourth in this case) in which the bases can not be paired. Write a program that will ask the user…