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W = -e-³x; W₁ = -e-²x(4+ ex)-¹; W₂ = e-x(4+ ex)-¹ We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁1 + U₂Y₂ is a particular solution. We can find the derivativ W₁ W U₁ U₂ = = -e-2x(4+ ex)-1 -e-3x W2 W e-x(4+ ex)-1 -e-3x

W = -e-³x; W₁ = -e-²x(4+ ex)-¹; W₂ = e-x(4+ ex)-¹ We want to find functions u₁(x) and u₂(x) such that yp = U₁Y₁1 + U₂Y₂ is a particular solution. We can find the derivativ W₁ W U₁ U₂ = = -e-2x(4+ ex)-1 -e-3x W2 W e-x(4+ ex)-1 -e-3x

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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We have found the following Wronskians. W = -e-³x; W₁ = −e−²×(4 + eX)−¹; W₂ = e¯×(4 + ex)−¹ We want to find functions u₁(x) and u₂(x) such that yµ = U₁Y₁ + U₂Y₂ is a particular solution. We can find the derivatives of these functions as follows. W₁ U₁ W -e-2x(4+ ex)-1 4₂ -3x W₂ W e-x(4+ ex)-1 -e-3x
Transcribed Image Text:We have found the following Wronskians. W = -e-³x; W₁ = −e−²×(4 + eX)−¹; W₂ = e¯×(4 + ex)−¹ We want to find functions u₁(x) and u₂(x) such that yµ = U₁Y₁ + U₂Y₂ is a particular solution. We can find the derivatives of these functions as follows. W₁ U₁ W -e-2x(4+ ex)-1 4₂ -3x W₂ W e-x(4+ ex)-1 -e-3x
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