w = 0.5 k/ft; P = 20 k; L = 80 ft; Sag-P = sag of cable under P = 3 ft 2) For the cable structure below: a) Solve for the reaction components b) Draw the shape of the cable under load c) Find the maximum tension in the cable and its location(s); minimum tension and its location(s); and maximum sag (downward displacement) and its location(s). Note that the sag (downward displacement) of the cable directly under the concentrated load is Sag-P. L/2 Reactions: V = HL = VR = HR = Maximum cable tension = Location(s) (x-coordinate(s))of maximum tension =, Minimum cable tension = Locations(s) (x-coordinate(s))of minimum tension = Maximum sag in cable = Locations(s) (x-coordinate(s))of maximum sag = Sag at centerline (x = L/2) =. 1.

w = 0.5 k/ft; P = 20 k; L = 80 ft; Sag-P = sag of cable under P = 3 ft 2) For the cable structure below: a) Solve for the reaction components b) Draw the shape of the cable under load c) Find the maximum tension in the cable and its location(s); minimum tension and its location(s); and maximum sag (downward displacement) and its location(s). Note that the sag (downward displacement) of the cable directly under the concentrated load is Sag-P. L/2 Reactions: V = HL = VR = HR = Maximum cable tension = Location(s) (x-coordinate(s))of maximum tension =, Minimum cable tension = Locations(s) (x-coordinate(s))of minimum tension = Maximum sag in cable = Locations(s) (x-coordinate(s))of maximum sag = Sag at centerline (x = L/2) =. 1.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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