(Vx-5 1. lim () x25 \x-25, x3+3x2+10x+104 2. lim X4 x2-12

Q: 7. (2x - 1)5 lim x → +∞ (3x² + 2x - 7)(x³ - 9x)

A:

Q: x4+5x+6 x-2x4+5x-6 lim

A: The given limit is a divergent and it does not exists

Q: lim V3n + 7"

A:

Q: limx-> 7((9x2-12x-13)/(x2-15))

A: We have to find limit means to put x is equal to limit point.

Q: x2 -x-2 lim 12 x- 2x X-2

A:

Q: Sfsin(r – y kýyd . B. (i) Evaluate 00 sVx+1 lim (ii) Evaluate * 4Vx +3

A:

Q: 5x + 4 Find lim X2 x - 3

A:

Q: 1 limx-0- (x 8 %3D x2

A:

Q: Vx2+5x-6 lim X-4 16-x2

A:

Q: lim(V9x² +x – 3x) Evaluate lim V9x² +x – 3x X00

A: Solve for the limit

Q: 4х+2 1. lim 9x² -3 2

A:

Q: – 5x I lim 2x(1–5x) 7x² +3

A:

Q: Vx²+1 +5x lim 2x+3 X→ -0 -1 3 1 2 1 2

A:

Q: x3/245 (B) Find limyJ+4

A:

Q: x² + 7x- 18 lim 6- 1 -69

A: Given

Q: lim + 4x - - X00

A:

Q: 10 a. lim 3-2 2x+1 b. lim Z x-3

A: Given 1.      lim x→3 10x-22.       lim x→2 2x-1x-3 To find - the value of the given limits

Q: Jx²+2 Lim X-7 3x -6

A:

Q: x-3x-2 limx--1 х+1 ||

A:

Q: - 2x3+ 3x-5x+1 lim 9. *-2

A: limx->-2x4-2x3+3x2-5x+1x2+4

Q: Vr2 + 8 – 3 lim I +1 2--1

A: We have to find limit

Q: (а) 5x-3 – 4 (i) Lim- x--00 2x-2 +9 (х— 3)2 (iї) Lim X-0 x2 7- 2x – 3 2х —

A: (i) Obtain the limit as follows.…

Q: lim Vx3 + 5x2 -10x + 25 10. *-4

A: The given expression is limx→ -4x3+5x2-10x+254