V(x) = 5 + 0.25.x ar force and x is length in distance along the beam. V = dM/dx, and M is the bending moment. Integration
V(x) = 5 + 0.25.x ar force and x is length in distance along the beam. V = dM/dx, and M is the bending moment. Integration
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![(1) A 10-m beam is subjected to a load, and the shear force follows the equation
V(x) = 5 + 0.25.r?
where V is the shear force and x is length in distance along the beam.
V =
dM/dx, and M is the bending moment. Integration yields the relationship
We know that
М — М, +
V dx
If Mo is zero and x =10 m, Calculate Musing (a) analytical integration, (b) trapezoidal rule (c) Simpson's
1/3rd rule. (Use 1 m increments).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ae03a05-360f-49e9-91f3-a4c13a1913d5%2F65221f1b-9c7d-4f1e-8cbb-7986d4155930%2Flz0e66md_processed.png&w=3840&q=75)
Transcribed Image Text:(1) A 10-m beam is subjected to a load, and the shear force follows the equation
V(x) = 5 + 0.25.r?
where V is the shear force and x is length in distance along the beam.
V =
dM/dx, and M is the bending moment. Integration yields the relationship
We know that
М — М, +
V dx
If Mo is zero and x =10 m, Calculate Musing (a) analytical integration, (b) trapezoidal rule (c) Simpson's
1/3rd rule. (Use 1 m increments).
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