v(t) 90 80 70 60 50 40 30 20 10 5 10 15 20 25 30 35 40 45 50 Time (seconds) v(t) (feet per second) (seconds) 10 15 20 25 30 35 40 45 50 12 20 30 55 70 78 81 75 60 72 The graph of the velocity v(t), in ft/sec, of a car traveling on a straight road, for 0St< 50, is shown above. A table of values for v(t), at 5 second intervals of time t, is shown to the right of the graph Velocity (feet per second)
v(t) 90 80 70 60 50 40 30 20 10 5 10 15 20 25 30 35 40 45 50 Time (seconds) v(t) (feet per second) (seconds) 10 15 20 25 30 35 40 45 50 12 20 30 55 70 78 81 75 60 72 The graph of the velocity v(t), in ft/sec, of a car traveling on a straight road, for 0St< 50, is shown above. A table of values for v(t), at 5 second intervals of time t, is shown to the right of the graph Velocity (feet per second)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Find the acceleration of Caren’s bicycle at time t=7.5 minutes. Indicate units of measure
Transcribed Image Text:v(t)
90
80
70
60
50
40
30
20
10
t
5 10 15 20 25 30 35 40 45 50
Time (seconds)
v(t)
(feet per second)
(seconds)
10
15
20
25
30
35
40
45
50
12
20
30
55
70
78
81
75
60
72
The graph of the velocity v(t), in ft/sec, of a car traveling on a straight road, for 0St< 50, is shown above. A table
of values for v(t), at 5 second intervals of time t, is shown to the right of the graph
Velocity
(feet per second)
Expert Solution
Step 1
Given:
A car is travelling on a straight road
Time t = 7.5 seconds
To determine:
Acceleration at time t = 7.5 second.
From table:
At time t = 5 seconds
v = 12 feet per second
At t = 20 seconds
v = 20 feet per second.
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