v(t) = 1.1t2 - 2.6t + 2.3 million hours of video per year (0 sts 9), time in years since the start of June 2005.t an expression for the total number of hours V(t) of video at time t (starting from zero hours of video at t = 0). (Round your coe the answer to part (a) to estimate the total number of hours of video uploaded by the start of 2014. (Round your answer to the million hours of video

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be approximated by
v(t) = 1.1t2 .
2.6t + 2.3 million hours of video per year
(0 sts 9),
where t is time in years since the start of June 2005.†
(a) Find an expression for the total number of hours V(t) of video at time t (starting from zero hours of video att = 0). (Round your coefficients to four decimal places.)
V(t) :
%D
(b) Use the answer to part (a) to estimate the total number of hours of video uploaded by the start of 2014. (Round your answer to the nearest million hours of video.)
million hours of video
Transcribed Image Text:Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be approximated by v(t) = 1.1t2 . 2.6t + 2.3 million hours of video per year (0 sts 9), where t is time in years since the start of June 2005.† (a) Find an expression for the total number of hours V(t) of video at time t (starting from zero hours of video att = 0). (Round your coefficients to four decimal places.) V(t) : %D (b) Use the answer to part (a) to estimate the total number of hours of video uploaded by the start of 2014. (Round your answer to the nearest million hours of video.) million hours of video
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