Vs1 R₁ ia R3 ww ic R₂ You are correct. Your receipt no. is 157-2141 ? Submit Answer Incorrect. Tries 1/5 Previous Tries id R4 You are correct. Your receipt no. is 157-9103 ? R5 Q5. In the circuit, Vs1 is 127 V, Vs2 is 68 V, R1 is 6 Ohm, R2 is 50 Ohm, R3 is 15 Ohm, R4 is 23 Ohm, R5 is 12 Oh (a) Find the current ia in the direction of the arrow. (Unit: A) 4.94A (b) Find the current ib in the direction of the arrow. (Unit: A) 2.0072 A Previous Tries ie (c) Find the current ic in the direction of the arrow. (Unit: A) 2.281A Submit Answer Incorrect. Tries 1/5 Previous Tries (d) Find the current id in the direction of the arrow. (Unit: A) 769 A Previous Tries + (e) Find the current ie in the direction of the arrow. (Unit: A) -0.4A Submit Answer Incorrect. Tries 1/9 Previous Tries Vs2

Vs1 R₁ ia R3 ww ic R₂ You are correct. Your receipt no. is 157-2141 ? Submit Answer Incorrect. Tries 1/5 Previous Tries id R4 You are correct. Your receipt no. is 157-9103 ? R5 Q5. In the circuit, Vs1 is 127 V, Vs2 is 68 V, R1 is 6 Ohm, R2 is 50 Ohm, R3 is 15 Ohm, R4 is 23 Ohm, R5 is 12 Oh (a) Find the current ia in the direction of the arrow. (Unit: A) 4.94A (b) Find the current ib in the direction of the arrow. (Unit: A) 2.0072 A Previous Tries ie (c) Find the current ic in the direction of the arrow. (Unit: A) 2.281A Submit Answer Incorrect. Tries 1/5 Previous Tries (d) Find the current id in the direction of the arrow. (Unit: A) 769 A Previous Tries + (e) Find the current ie in the direction of the arrow. (Unit: A) -0.4A Submit Answer Incorrect. Tries 1/9 Previous Tries Vs2

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Concept explainers

BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.

Question

I calculated 97.38V for V1 and 63.16V for V2. Where did I go wrong for calculating ia, ic, and ie?

R₁₁
ia
+
ic
R₂
R4
Vs2
ib
*OWER WER ON
Vs1
R3
ww
Q5. In the circuit, Vs1 is 127 V, Vs2 is 68 V, R1 is 6 Ohm, R2 is 50 Ohm, R3 is 15 Ohm, R4 is 23 Ohm, R5 is 12 Ohm.
(a) Find the current ia in the direction of the arrow. (Unit: A)
4.94A
Submit Answer Incorrect. Tries 1/5 Previous Tries
You are correct.
Your receipt no. is 157-2141 ?
(b) Find the current ib in the direction of the arrow. (Unit: A)
2.0072 A
R5
ww
ie
Previous Tries
You are correct.
Your receipt no. is 157-9103 ?
(c) Find the current ic in the direction of the arrow. (Unit: A)
2.281A
Submit Answer Incorrect. Tries 1/5 Previous Tries
(d) Find the current id in the direction of the arrow. (Unit: A)
2.7769 A
Previous Tries
(e) Find the current ie in the direction of the arrow. (Unit: A)
-0.4A
Submit Answer Incorrect. Tries 1/9 Previous Tries

05.
VS2+)
at V₂
₁-127
6
1
V₂ (7)
at vz
10
12-68
12
+
230
15
V₁
+
קל
Ka
4.13
V2
23
33-
+
→ V₁ (0.253).
Ohm
1.7A
h3
AAAAA
il
(₂)
R5
مل
le
V₂-V₂0
15
+
=1/50 + √5) - 12 = 122
15
By
-0.067v1
+
VS2
+V₁V₁=0
15
0.067 v2 2 21.167
V₂ ( 1/2 + 2/3+1/5) - 1/12 = 12
15
V₂ (0.193) -0.06702= 5.667
nude
Ohr
Vs1=127v
R₁ = 6 ohm R₂ = 50
Ry = 15 ohm Ry= 23 ohm
R5= 12 ohm
5.667-193V2
7A
VS2 = 68v
ohm
0 V₂ = 63.16
Va= -84.582 +2.881 v22 97.38V
16 =
ib=
VS1-V₁2
FI
V1-0
k₂
10 = -√₂
12-0
2
iez V₂-Usz
K-5
127-97.38
-6
97.58-0-1.95 A
50
97.38-63.16
= 4.94A
23
63.16-0-2.75 A
63.16-68
12
2.281 A
= -0.403A

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Step 4: a. Find the current i_a.

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Step 5: b. Find the current i_b.

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Step 6: c. Find the current i_c.

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