VS 1 Vpk 100 Hz ODeg 2.2uF IC=OV R1 m 1000 C2 1uF IC=OV >R2 2200

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Determine the current and voltages using the circuit below . Put in polar and rectangular form
**Transcription for Educational Website:**

---

**Circuit Diagram Explanation:**

This is a basic R-C (Resistor-Capacitor) AC circuit used to illustrate the flow of alternating current (AC) through passive components like resistors and capacitors.

**Components and Configuration:**

1. **Voltage Source (VS):**
   - Amplitude: 1 Vpk (Volt peak)
   - Frequency: 100 Hz
   - Phase: 0 degrees

2. **Capacitor C1:**
   - Capacitance: 2.2 microfarads (μF)
   - Initial Condition (IC): 0 volts

3. **Resistor R1:**
   - Resistance: 100 ohms (Ω)

4. **Capacitor C2:**
   - Capacitance: 1 microfarad (μF)
   - Initial Condition (IC): 0 volts

5. **Resistor R2:**
   - Resistance: 220 ohms (Ω)

**Circuit Path:**

- The AC voltage source provides an alternating current with a peak voltage of 1V, oscillating at 100 Hz.
- The current first passes through Capacitor C1 (2.2μF), which initially holds no charge as its initial condition is marked at 0V.
- Following C1, the current flows through Resistor R1 (100Ω).
- After R1, the path continues through Capacitor C2 (1μF), also starting with no charge (IC = 0V).
- Finally, the circuit completes through Resistor R2 (220Ω), which connects to the ground.

**Purpose and Application:**

This circuit can be used to demonstrate the behavior of capacitors and resistors in AC circuits, such as how capacitors charge and discharge with time and how resistors dissipate energy. It serves as a foundational example in studies of AC circuit design and analysis.
Transcribed Image Text:**Transcription for Educational Website:** --- **Circuit Diagram Explanation:** This is a basic R-C (Resistor-Capacitor) AC circuit used to illustrate the flow of alternating current (AC) through passive components like resistors and capacitors. **Components and Configuration:** 1. **Voltage Source (VS):** - Amplitude: 1 Vpk (Volt peak) - Frequency: 100 Hz - Phase: 0 degrees 2. **Capacitor C1:** - Capacitance: 2.2 microfarads (μF) - Initial Condition (IC): 0 volts 3. **Resistor R1:** - Resistance: 100 ohms (Ω) 4. **Capacitor C2:** - Capacitance: 1 microfarad (μF) - Initial Condition (IC): 0 volts 5. **Resistor R2:** - Resistance: 220 ohms (Ω) **Circuit Path:** - The AC voltage source provides an alternating current with a peak voltage of 1V, oscillating at 100 Hz. - The current first passes through Capacitor C1 (2.2μF), which initially holds no charge as its initial condition is marked at 0V. - Following C1, the current flows through Resistor R1 (100Ω). - After R1, the path continues through Capacitor C2 (1μF), also starting with no charge (IC = 0V). - Finally, the circuit completes through Resistor R2 (220Ω), which connects to the ground. **Purpose and Application:** This circuit can be used to demonstrate the behavior of capacitors and resistors in AC circuits, such as how capacitors charge and discharge with time and how resistors dissipate energy. It serves as a foundational example in studies of AC circuit design and analysis.
The table provided is structured to display calculations for circuit values at two different frequencies: 1 kHz and 10 kHz. It is organized into columns for rectangular and polar forms under each frequency. Below is a transcription of the table content:

### Table Header:
- **Frequency (f) = 1 kHz**
  - **Rectangular**
  - **Polar**
- **Frequency (f) = 10 kHz**
  - **Rectangular**
  - **Polar**

### Circuit Value Equations:
1. \( X_{C1} = 1 / [2\pi(f)(C_1)] \)
2. \( X_{C2} = 1 / [2\pi(f)(C_2)] \)
3. \( R_T = R_1 + R_2 \)
4. \( X_{CT} = X_{C1} + X_{C2} \)
5. \( Z_T = R_T + jX_{CT} \)
6. \( I_T = V_S / Z_T \)
7. \( V_{C1} = I_T \times X_{C1} \)
8. \( V_{C2} = I_T \times X_{C2} \)
9. \( V_{R1} = I_T \times R_1 \)
10. \( V_{R2} = I_T \times R_2 \)

### Graph/Diagram Description:
There is no graph or diagram present in this table; it consists solely of placeholders for calculations based on the given formulas. The table is likely used in educational settings for illustrating calculations of reactance, impedance, current, and voltage values in electric circuits at different frequencies.

This layout supports students in learning how to compute these values in both rectangular and polar forms, enhancing their understanding of electrical circuit analysis.
Transcribed Image Text:The table provided is structured to display calculations for circuit values at two different frequencies: 1 kHz and 10 kHz. It is organized into columns for rectangular and polar forms under each frequency. Below is a transcription of the table content: ### Table Header: - **Frequency (f) = 1 kHz** - **Rectangular** - **Polar** - **Frequency (f) = 10 kHz** - **Rectangular** - **Polar** ### Circuit Value Equations: 1. \( X_{C1} = 1 / [2\pi(f)(C_1)] \) 2. \( X_{C2} = 1 / [2\pi(f)(C_2)] \) 3. \( R_T = R_1 + R_2 \) 4. \( X_{CT} = X_{C1} + X_{C2} \) 5. \( Z_T = R_T + jX_{CT} \) 6. \( I_T = V_S / Z_T \) 7. \( V_{C1} = I_T \times X_{C1} \) 8. \( V_{C2} = I_T \times X_{C2} \) 9. \( V_{R1} = I_T \times R_1 \) 10. \( V_{R2} = I_T \times R_2 \) ### Graph/Diagram Description: There is no graph or diagram present in this table; it consists solely of placeholders for calculations based on the given formulas. The table is likely used in educational settings for illustrating calculations of reactance, impedance, current, and voltage values in electric circuits at different frequencies. This layout supports students in learning how to compute these values in both rectangular and polar forms, enhancing their understanding of electrical circuit analysis.
Expert Solution
Step 1: Stating the given data

Given circuit:

Electrical Engineering homework question answer, step 1, image 1

Asked to find the,

  • Capacitive reactance of C1
  • Capacitive reactance of C2,
  • Total resistance
  • Total capacitive reactance

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