Vr2 – x², whose graph is the upper 6. Let r > 0 be a real number. Suppose y = semi-circle of radius r about the origin. f(x) (a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+ f'(x)². (b) Suppose –r < a < b < r. Calculate the surface area of the portion of the sphere of radius r between x = a and x = b. (c) Imagine cutting a spherical orange by equidistant parallel planes. (An orange cut into nine equal-width pieces is shown.) Which pieces do you expect to have the most rind: Those near “the poles", or those near "“the equator"? How does your intuition compare with the result of (b)?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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= vr2 – x2, whose graph is the upper
6. Let r > 0 be a real number. Suppose y =
semi-circle of radius r about the origin.
f (x)
(a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+ f'(x)².
(b) Suppose -r < a < b < r. Calculate the surface area of the portion of the sphere of
radius r between x = a and x =
= b.
(c) Imagine cutting a spherical orange by equidistant parallel planes. (An orange cut into
nine equal-width pieces is shown.) Which pieces do you expect to have the most rind:
Those near "the poles", or those near "the equator"? How does your intuition compare
with the result of (b)?
Transcribed Image Text:= vr2 – x2, whose graph is the upper 6. Let r > 0 be a real number. Suppose y = semi-circle of radius r about the origin. f (x) (a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+ f'(x)². (b) Suppose -r < a < b < r. Calculate the surface area of the portion of the sphere of radius r between x = a and x = = b. (c) Imagine cutting a spherical orange by equidistant parallel planes. (An orange cut into nine equal-width pieces is shown.) Which pieces do you expect to have the most rind: Those near "the poles", or those near "the equator"? How does your intuition compare with the result of (b)?
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