void swap(int n1, int n2) { int temp = n1; n1 = n2; n2 = temp; } void swap(int a[]) { int temp = a[0]; a[0] = a[1]; a[1] = temp; %3D int main() { int a[] = {10, 20}; swap(a[0], a[1]); cout << "a[0]="< a[0] << endl; cout << "a[1]= "< a[1] << endl; swap(a); cout << "a[0]= "< a[0] << endl; cout << "a[1]= "< a[1] << endl; return 0; %3D
void swap(int n1, int n2) { int temp = n1; n1 = n2; n2 = temp; } void swap(int a[]) { int temp = a[0]; a[0] = a[1]; a[1] = temp; %3D int main() { int a[] = {10, 20}; swap(a[0], a[1]); cout << "a[0]="< a[0] << endl; cout << "a[1]= "< a[1] << endl; swap(a); cout << "a[0]= "< a[0] << endl; cout << "a[1]= "< a[1] << endl; return 0; %3D
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Show the printout of the following codes with only one character per cell.
![void swap(int n1, int n2)
{
int temp = n1;
n1 = n2;
n2 = temp;
}
void swap(int a[])
{
int temp = a[0];
a[0] = a[1];
a[1] = temp;
}
int main()
{
int a[] = {10, 20};
swap(a[0], a[1]);
cout << "a[0]="< a[0] << endl;
cout << "a[1]= "< a[1] << endl;
swap(a);
cout << "a[0]= "< a[0] << endl;
cout << "a[1]= "<< a[1] << endl;
return 0;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba58f2f6-b073-4116-825c-d767067833db%2Ff4221655-e78f-4dfe-a359-e889c2c1d474%2Fi6ixkbx_processed.png&w=3840&q=75)
Transcribed Image Text:void swap(int n1, int n2)
{
int temp = n1;
n1 = n2;
n2 = temp;
}
void swap(int a[])
{
int temp = a[0];
a[0] = a[1];
a[1] = temp;
}
int main()
{
int a[] = {10, 20};
swap(a[0], a[1]);
cout << "a[0]="< a[0] << endl;
cout << "a[1]= "< a[1] << endl;
swap(a);
cout << "a[0]= "< a[0] << endl;
cout << "a[1]= "<< a[1] << endl;
return 0;
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