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void baz(int a, int * p) { int c; c = a-*p; if (c) { } int d = c*2; *p -= d; (continued on next page) pushq %rbp movq %rsp,%rbp subq $16,%rsp movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax), %eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) movl 24(%rbp),%rax movl (%rax), %eax -8(%rbp),%eax %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: subl movl

void baz(int a, int * p) { int c; c = a-*p; if (c) { } int d = c*2; *p -= d; (continued on next page) pushq %rbp movq %rsp,%rbp subq $16,%rsp movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax), %eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) movl 24(%rbp),%rax movl (%rax), %eax -8(%rbp),%eax %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: subl movl

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I need help with this assembly code / C code question showing below

void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; c = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: } (continued on next page)
Transcribed Image Text:void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; c = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: } (continued on next page)
else { int e = "p/2; L2: movq 24(%rbp),%rax movl (%rax),%eax movl %eax, %edx shrl $31, %edx addl %edx, %eax sarl %eax movl %eax,-12(%rbp) *p += e-a; movl 24(%rbp),%rax movl (%rax), %edx movl -12(%rbp), %eax subl 16(%rbp),%eax addl %eax,%edx movq 24(%rbp), %rax movl %edx,(%rax) L4: addq $16, %rsp popq %rbp ret } 3. Registers Rewrite the preceding example using as many registers as is reasonable. If you use any callee save registers, remember to add the save code.
Transcribed Image Text:else { int e = "p/2; L2: movq 24(%rbp),%rax movl (%rax),%eax movl %eax, %edx shrl $31, %edx addl %edx, %eax sarl %eax movl %eax,-12(%rbp) *p += e-a; movl 24(%rbp),%rax movl (%rax), %edx movl -12(%rbp), %eax subl 16(%rbp),%eax addl %eax,%edx movq 24(%rbp), %rax movl %edx,(%rax) L4: addq $16, %rsp popq %rbp ret } 3. Registers Rewrite the preceding example using as many registers as is reasonable. If you use any callee save registers, remember to add the save code.
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