vo coplanar and concentric circular loops of wire carry curre et r, = 12.0 cm and r, = 8.50 cm. (Assume the positive dim owards you) and assume the positive vertical direction is to
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
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In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
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 alt="Two coplanar and concentric circular loops of wire carry currents of I, = 6.10 A and I, = 2.10 A in opposite directions as in the figure below.
Let r, = 12.0 cm and r, = 8.50 cm. (Assume the positive direction along the axis perpendicular to the faces of the loops is out of the screen
(towards you) and assume the positive vertical direction is toward the top of the screen.)
(a) What is the magnitude of the net magnetic field (in pT) at the center of the two loops?
1.64E-5
Recall that the magnetic field at the center of a circular current loop of radius R and carrying current I is B = "o. Use this
2R
relationship for both loops, and apply the right-hand rule to determine the directions of the field due to each loop. µT
(b) What is the direction of the net magnetic field at the center of the two loops?
out of the screen
into the screen
toward the top of the screen
toward the bottom of the screen
(c) Let r, remain fixed at 12.0 cm and let r, be a variable. Determine the value of r, (in cm) such that the net field at the center of the
loops is zero.
| 4.13
cm
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