Visible light of frequency f = 5 × 10¹4 Hz is beamed directly at a metal reflector. Light is traveling in oil, where its speed is 1.5 x 108 m/s. a) Calculate the wavelength of the visible light. A = b) Consider A = 6 x 107 m. The spacing Ax between successive antinodes in the resulting standing-wave pattern is given by: c) m 6 x 10-7 2 Calculate Δ.r. 6 x 10-7 3 6 x 10-7 4

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Chapter16: Electromagnetic Waves
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Problem 2
This problem is composed of two independent parts.
For all parts of this problem, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY
A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS).
Part 1
Visible light of frequency f = 5 x 10¹4 Hz is beamed directly at a metal reflector. Light is traveling in oil,
where its speed is 1.5 × 108 m/s.
a)
Calculate the wavelength of the visible light.
A =
b)
Consider λ = 6 x 107 m. The spacing Ax between successive antinodes in the resulting
standing-wave pattern is given by:
6 x 10-7
2
c)
Ar =
a)
E₁ =
m
b)
E₂ =
Calculate Δ.r,
Part 2
A standing wave is given by E= 400 sin(7.14 x) cos(11.42 t). Two waves E₁ and E₂ can be
superimposed to generate this standing wave.
x =
m
Determine the wave E₁ as per the below:
sin(
6 x 10-7
3
X-
m
Determine the wave E₂ as per the below:
sin(
t)
x+
6 x 10-7
4
c)
The wavelength of this wave is 0.87 m. For a>0, what is the location of the antinode
having the smallest value of x?
Transcribed Image Text:Problem 2 This problem is composed of two independent parts. For all parts of this problem, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). Part 1 Visible light of frequency f = 5 x 10¹4 Hz is beamed directly at a metal reflector. Light is traveling in oil, where its speed is 1.5 × 108 m/s. a) Calculate the wavelength of the visible light. A = b) Consider λ = 6 x 107 m. The spacing Ax between successive antinodes in the resulting standing-wave pattern is given by: 6 x 10-7 2 c) Ar = a) E₁ = m b) E₂ = Calculate Δ.r, Part 2 A standing wave is given by E= 400 sin(7.14 x) cos(11.42 t). Two waves E₁ and E₂ can be superimposed to generate this standing wave. x = m Determine the wave E₁ as per the below: sin( 6 x 10-7 3 X- m Determine the wave E₂ as per the below: sin( t) x+ 6 x 10-7 4 c) The wavelength of this wave is 0.87 m. For a>0, what is the location of the antinode having the smallest value of x?
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