ViS2 (s) = Vi** (aq) + 2S²-(aq) K. = 3.64 x 10-8 What is the concentration of Vi*(aq) in a solution in equilibrium with solid vibranium sulfide where the initial vibranium ion concentration was zero and the initial sulfide ion concentration was 3.20 x 104? Please express your answer in mM to three SF. Your Answer: Answer units

Chemistry
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Chapter13: Chemical Equilibrium
Section: Chapter Questions
Problem 85AE: Suppose K = 4.5 103 at a certain temperature for the reaction PCl5(g)PCl3(g)+Cl2(g) If it is found...
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ViS2 (s) = Vi** (aq) + 2S²-(aq)
Ke = 3.64 x 10~8
What is the concentration of Vi*(aq) in a solution in equilibrium with solid vibranium sulfide
where the initial vibranium ion concentration was zero and the initial sulfide ion concentration
was 3.20 x 104? Please express your answer in mM to three SF.
Your Answer:
Answer
units
Transcribed Image Text:ViS2 (s) = Vi** (aq) + 2S²-(aq) Ke = 3.64 x 10~8 What is the concentration of Vi*(aq) in a solution in equilibrium with solid vibranium sulfide where the initial vibranium ion concentration was zero and the initial sulfide ion concentration was 3.20 x 104? Please express your answer in mM to three SF. Your Answer: Answer units
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